Problem 8: A capacitor of capacitance C-10 uF has been charged so that thepotential difference between its plates is Vo 380 V. The capacitor is then connected to aresistor of resistance R-6.5 k2. The switch S is closed, and the capacitor begins todischargeRandomized VariablesVo 380 Vl-©theexpertta.comΔPart (a) Calculate the time constant of the circuit in seconds.tan()cos0)cotanasin) acos(0atan() acotan sinh()cosh)tanh cotanh)O Degrees O RadianssinHOME4 5 60BACKSPACECLEARSubmitHintI give up!Hints: 1%, deduction per hint. Hints remaining: 2Feedback: 1% deduction per feedback.a Part (b) Calculate the charge Qo on the capacitor before the switch is closed, incoulombs.Part (c) Calculate the current Io immediately after the switch is closed, in amperes.. Part (d) Calculate the potential difference VC in volts between the capacitor plates attime t - 5.0 ms after the switch is closedA Part (e) Calculate the time T in s after which the charge on the capacitor hasdecreased to one fourth its maximum value.

Given: Capacitance, C = 10 microfaradPotential difference, Vo = 380VResistance, R = 6.5 kilo-ohm

Answered: Problem 8: A capacitor of capacitance…

Modern Physics

3rd Edition

ISBN:9781111794378

Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Chapter12: The Solid State

Section: Chapter Questions

Problem 12P

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