In the circuit of the figure:- \( \mathcal{E} = 1.70 \text{ kV} \)- \( C = 9.50 \, \mu\text{F} \)- \( R_1 = R_2 = R_3 = 0.750 \, \text{M}\Omega \)With \( C \) completely uncharged, switch \( S \) is suddenly closed (at \( t = 0 \)).At \( t = 0 \), what are:- (a) the current \( i_1 \) in resistor 1?- (b) the current \( i_2 \) in resistor 2?- (c) the current \( i_3 \) in resistor 3?At \( t = \infty \) (after many time constants), what are:- (d) \( i_1 \)?- (e) \( i_2 \)?- (f) \( i_3 \)?What is the potential difference \( V_2 \) across resistor 2 at:- (g) \( t = 0 \)?- (h) \( t = \infty \)?**Diagram Explanation**:The circuit diagram consists of a battery (\( \mathcal{E} \)), three resistors (\( R_1, R_2, R_3 \)), a capacitor (\( C \)), and a switch (\( S \)). Initially, the capacitor is uncharged. The switch controls the connection between the circuit elements. When closed, current can flow, charging the capacitor over time.**Answer Fields**:Below the description, fields are provided to enter numerical values for each question part. Each entry requires a number followed by selecting the appropriate units from a dropdown menu.

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Answered: In the circuit of the figure & = 1.70…

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