In the circuit shown, ε = 4V, R₁ =43 2, R2 = 72 , and C= 14 uF.-Initially, the capacitor is uncharged and the switchis open. At t=0, the switch is closed. The positivedirections of the currents are represented by thearrows in the diagram.(a) What is the current running out of thebattery at t= 0s?1₁*TER₁I3*+ 12R₂(b) After the switch has been closed for a long time, calculate 11, 12, 13, and Qtot(the total charge on the capacitor). In your answer, please use the namingconvention for the currents shown in the diagram.

Voltage of battery (V) = 4V R1= 43 ohm. R2= 72 ohm. C= 14 micro farad.

Answered: In the circuit shown, E = 4V, R₁ =43,…

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