In the circuit shown, there are two resistors, with R = 5.0 k2 and R2 = 10.0 k2, along with a capacitor, with C= 15.0 uF, initially uncharged, parallel to the second resistor. The battery supplies a voltage of E=30.0 V. The switch is closed at t= 0. (a) At that instant, what is the current in each resistor? What are the final (b) currents and (c) charge on the capcitor when the switch has been closed for a long time? (d) When the switch is re-opened, what is the time-constant for the discharging capacitor? +

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The text describes an electrical circuit problem involving a configuration with resistors, a capacitor, and a battery. Here's the transcription of the content, suitable for an educational website:

---

### Circuit Analysis Problem

**Problem Statement:**

In the circuit shown, there are two resistors, with \( R_1 = 5.0 \, \text{k}\Omega \) and \( R_2 = 10.0 \, \text{k}\Omega \), along with a capacitor, \( C = 15.0 \, \mu\text{F} \), initially uncharged, parallel to the second resistor. The battery supplies a voltage of \( \mathcal{E} = 30.0 \, \text{V} \). The switch is closed at \( t = 0 \).

**Questions:**

(a) At that instant, what is the current in each resistor?

(b) What are the final currents and

(c) the charge on the capacitor when the switch has been closed for a long time?

(d) When the switch is re-opened, what is the time constant for the discharging capacitor?

**Diagram Explanation:**

- **Components**: 
  - Battery (\( \mathcal{E} = 30.0 \, \text{V} \))
  - Resistor \( R_1 = 5.0 \, \text{k}\Omega \)
  - Resistor \( R_2 = 10.0 \, \text{k}\Omega \)
  - Capacitor \( C = 15.0 \, \mu\text{F} \)
  - Switch (denoted as \( S \)), initially open

- **Connections**:
  - The switch \( S \) is connected in series with \( R_1 \).
  - The capacitor \( C \) is connected in parallel with \( R_2 \).

When the switch is closed, the current flows through \( R_1 \) and \( R_2 \), and begins charging the capacitor \( C \).

---

This structure ensures clear understanding and focus on the problem-solving aspects for educational purposes.
Transcribed Image Text:The text describes an electrical circuit problem involving a configuration with resistors, a capacitor, and a battery. Here's the transcription of the content, suitable for an educational website: --- ### Circuit Analysis Problem **Problem Statement:** In the circuit shown, there are two resistors, with \( R_1 = 5.0 \, \text{k}\Omega \) and \( R_2 = 10.0 \, \text{k}\Omega \), along with a capacitor, \( C = 15.0 \, \mu\text{F} \), initially uncharged, parallel to the second resistor. The battery supplies a voltage of \( \mathcal{E} = 30.0 \, \text{V} \). The switch is closed at \( t = 0 \). **Questions:** (a) At that instant, what is the current in each resistor? (b) What are the final currents and (c) the charge on the capacitor when the switch has been closed for a long time? (d) When the switch is re-opened, what is the time constant for the discharging capacitor? **Diagram Explanation:** - **Components**: - Battery (\( \mathcal{E} = 30.0 \, \text{V} \)) - Resistor \( R_1 = 5.0 \, \text{k}\Omega \) - Resistor \( R_2 = 10.0 \, \text{k}\Omega \) - Capacitor \( C = 15.0 \, \mu\text{F} \) - Switch (denoted as \( S \)), initially open - **Connections**: - The switch \( S \) is connected in series with \( R_1 \). - The capacitor \( C \) is connected in parallel with \( R_2 \). When the switch is closed, the current flows through \( R_1 \) and \( R_2 \), and begins charging the capacitor \( C \). --- This structure ensures clear understanding and focus on the problem-solving aspects for educational purposes.
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