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For each expression, find the positive real value ofw that would cause Reg to be purely real, as well as the resulting Reg. Note that ab // is the binary operator that finds the equivalent resistance of two resistors in parallel (i.e. a//b= (a+b)) [Hint: For (a), try setting the imaginary coordinate to be zero. For (b), try equating the numerator and denominator angles). Note: In this problem, you may only submit numerical answers. (i.e. If 4 is the correct answer, 4 will be marked as correct, but 2+2 will be marked as incorrect.) a. Reg 1 j.7.3w b. Req (0.6+ 3 +(j-20.628w)//3.9 1 j.7.3w and Ret -)//(j-20.628w) and Reg E

For each expression, find the positive real value ofw that would cause Reg to be purely real, as well as the resulting Reg. Note that ab // is the binary operator that finds the equivalent resistance of two resistors in parallel (i.e. a//b= (a+b)) [Hint: For (a), try setting the imaginary coordinate to be zero. For (b), try equating the numerator and denominator angles). Note: In this problem, you may only submit numerical answers. (i.e. If 4 is the correct answer, 4 will be marked as correct, but 2+2 will be marked as incorrect.) a. Reg 1 j.7.3w b. Req (0.6+ 3 +(j-20.628w)//3.9 1 j.7.3w and Ret -)//(j-20.628w) and Reg E

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For each expression, find the positive real value ofw that would cause Reg to be purely real, as well as the resulting Reg. Note that ab // is the binary operator that finds the equivalent resistance of two resistors in parallel (i.e. a//b= (a+b)). [Hint: For (a), try setting the imaginary coordinate to be zero. For (b), try equating the numerator and denominator angles). Note: In this problem, you may only submit numerical answers. (i.e. If 4 is the correct answer, 4 will be marked as correct, but 2+2 will be marked as incorrect.) a. Reg = لا 1 j-7.3w b. Req (0.6+ 3 +(j-20.628w)//3.9 1 j-7.3w and Ret -)//(j-20.628w) and Reg E
Transcribed Image Text:For each expression, find the positive real value ofw that would cause Reg to be purely real, as well as the resulting Reg. Note that ab // is the binary operator that finds the equivalent resistance of two resistors in parallel (i.e. a//b= (a+b)). [Hint: For (a), try setting the imaginary coordinate to be zero. For (b), try equating the numerator and denominator angles). Note: In this problem, you may only submit numerical answers. (i.e. If 4 is the correct answer, 4 will be marked as correct, but 2+2 will be marked as incorrect.) a. Reg = لا 1 j-7.3w b. Req (0.6+ 3 +(j-20.628w)//3.9 1 j-7.3w and Ret -)//(j-20.628w) and Reg E
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