Voltage No. of Breaker Poles Pu Rating Circuits Ratings 208/120 V 19 30, 4 W 208/120 V 24 3 0,4 W 208/120 V 24 3o, 4 W 208/120 V 36, 4 W 1252NOŹNONC 20 A 1 Lighting a 20 A 2 Receptacl 20 A 1 Spares 20 A 1 Lighting a 20 A 2 Receptacl 0 Spares 20 A 1 Lighting a 20 A 2 Receptacl 0 Spares 24 20 A 1 Lighting a 20 A 2 Receptacl n s the same as for two single-pole breakers. ule of electric panelboards for the industrial building. Mains Voltage Panelboard Location No. P-1 Basement Breaker N. Corridor 100 A P-2 1st Floor Breaker N. Corridor 100 A P-3 2nd Floor Breaker N. Corridor 100 A P-4 Basement Breaker S. Corridor 100 A Rating 208/120 V 36, 4 W 208/120 V 3, 4 W 208/120 V 3 %, 4 W 208/120 V 36, 4 W ere a 2-pole circuit breaker is used, the space required is the same as fo

Voltage No. of Breaker Poles Pu Rating Circuits Ratings 208/120 V 19 30, 4 W 208/120 V 24 3 0,4 W 208/120 V 24 3o, 4 W 208/120 V 36, 4 W 1252NOŹNONC 20 A 1 Lighting a 20 A 2 Receptacl 20 A 1 Spares 20 A 1 Lighting a 20 A 2 Receptacl 0 Spares 20 A 1 Lighting a 20 A 2 Receptacl 0 Spares 24 20 A 1 Lighting a 20 A 2 Receptacl n s the same as for two single-pole breakers. ule of electric panelboards for the industrial building. Mains Voltage Panelboard Location No. P-1 Basement Breaker N. Corridor 100 A P-2 1st Floor Breaker N. Corridor 100 A P-3 2nd Floor Breaker N. Corridor 100 A P-4 Basement Breaker S. Corridor 100 A Rating 208/120 V 36, 4 W 208/120 V 3, 4 W 208/120 V 3 %, 4 W 208/120 V 36, 4 W ere a 2-pole circuit breaker is used, the space required is the same as fo

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.9MCQ: Match the following: (i) Hysteresis loss (a) Can be redud by constructing the core with laminated...

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Draw three transformers for each of the different three-phase connections. That is, draw three transformers and then make the connection, eg star-star, then redraw three transformers and make another three-phase connection, and so on until all four combinations of three-phase connections are made.
For the given circuit in figure, data is mentioned. Find the fault current when the system is unloaded when the fault occurs at terminal P.
Determine the short-circuit current ISC3,0.4kV for a 3-phase short- circuit fault at F. Give your answer up to 2 decimal in kA but do not enter the unit in your answer. Transformer T1 Transformer T2 Cable C1 Isc3,6.6kV Isc3.0.4kV O + j0.150 F 1 MVA 2 MVA 22/6.6kV 25 MVA fault level 6.6 kV/400V Z=3% 6.6 kV switchboard 400 V switchboard
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imary winding is connected o be applied at normal freq rough it when the secondary conner loss
6. For the air core transformer circuit shown below, determine the currents la and lb in the direction shown. Express each answer in polar form. R1-302 www la ZI1=150 E=10/0 M=j20 Ze= n Z12=j62 lb R2=50 la Ib
O Van lags Vbn. and V bn lags Ven- O Van lags Vbn, and Vin leads Ven- Question 11 A transformer with a primary voltage V = 15Z15° V has a turns ratio of 1:5. What is the secondary voltage, V2? O 75/75° V O 3/15° V O 3275° V O 75/15° V PrtScn F5 F6 F7
QUESTION 19 E-06, PC-02. Three inductors 15 mH, 15 mH and 15 mH are connected in series. What is the total inductance? O 5 mH. Without knowing the coupling factor the total inductance cannot be found. 45mH. QUESTION 20 E-06, PC-05. Why are the iron cores of most induction coils laminated? To increase the core permeability. O To reduce the core reluctance. O To reduce the effects of eddy currents. Click Save and Submit to save and submit. Click Save All Answers to save all answers. MacBook Air 888 F7 FB F6 F4 F3 F2 & 23 $ 4 5 0 8 3 Y W E と S D S F G >> J しのくつつ >
Tutorial 1.7 The three-phase ratings of a three-winding transformer are: Primary Y-connected, 66 kV, 24 MVA Y-connected, 13.2 kV, 12 MVA Secondary Tertiary A-connected, 2.3 kV, 4 MVA Neglecting resistance, the leakage impedances are: Zps Zns = 6% on 24 MVA, 66 kV base Zpt = 8% on 24 MVA, 66 kV base Zst = 7% on 12 MVA, 13.2 kV base Find the per-unit impedances of the per-phase equivalent circuit for a base of 24 MVA, 66 kV in the primary circuit. {Ans: j 0.0; j 0.06; j 0.08}
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