A light bulb manufacturer guarantees that the mean life of a certain type of light bulb is at least 761 hours. A randomsample of 23 light bulbs has a mean life of 748 hours. Assume the population is normally distributed and thepopulation standard deviation is 60 hours. At a = 0.02, do you have enough evidence to reject the manufacturer'sclaim? Complete parts (a) through (e).(a) Identify the null hypothesis and alternative hypothesis.OA. Ho: 2761 (claim)Ha: H <761OD. Ho: <748 (claim)Ημ2748OB. Ho: >761Ha: HS761 (claim)O E. Ho: #761(claim)H₂=761OC. Ho: H=748Ha: #748 (claim)OF. Ho: μ≤748H₂: >748 (claim)

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Answered: type A random guarantees that the mean…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 69 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 121 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H₂. Choose the correct answer below. OA. Ho: >870 (claim) H₂: H≤870 OC. Ho: μ≤900 Ha: >900 (claim) E. Ho: H≤870 H: >870 (claim) OB. Ho: H=900 OA. The rejection region is z> 1.64. OB. The rejection region is z 1.64. H₂: #900 (claim) OD. Ho: H=870 (claim) Ha: 870 OF. Ho: >900 (claim) Ha: HS900 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical value is 1.64. OB. The critical values are t Identify the rejection…
Test a claim that the mean amount of carbon monoxide in the air in U.S. cities is less than 2.31 parts per million. It was found that the mean amount of carbon monoxide in the air for the random sample of 66 cities is 2.37 parts per million and the standard deviation is 2.11 parts per million. At α=0.05, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed. (a) Identify the claim and state H0 and Ha. Which of the following correctly states H0 and Ha? The claim is the ( null) ( alternative) hypothesis (b) Use technology to find the critical value(s) and choose the graph that shows the rejection region (c) Find the standardized test statistic, t. (d) Decide whether to reject or fail to reject the null hypothesis. (e) Interpret the decision in the context of the original claim.
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A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 61 residential customers has a mean monthly consumption of 920 kWh. Assume the population standard deviation is 127 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H₂. Choose the correct answer below. OA. Ho: H=890 (claim) H₂: *890 OC. Ho: >890 (claim) Ha: μ≤ 890 OE. Ho: 920 Ha: #920 (claim) OB. Ho: ≤920 Ha: >920 (claim) O D. Ho: > 920 (claim) Ha: μS920 At the 1% significance level, there electricity consumption in a certain region OF. Ho: s890 OA. The rejection region is z 2.33. OC. The rejection region is z>2.33. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z =. (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. (b) Find the critical…
A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 67 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 120 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and Ha. Choose the correct answer below. O A. Ho: µ= 870 (claim) Hạ: H#870 B. Ho: H5870 > 870 (claim) O C. Ho: H> 870 (claim) Ha: u5870 D. Ho: Hs 900 Ha: µ> 900 (claim) O E. Ho: µ> 900 (claim) ΟF Ho: μ= 900 Ha: µ# 900 (claim) Ha: HS 900 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical values are ± B. The critical value is
A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 68 residential customers has a mean monthly consumption of 930 kWh. Assume the population standard deviation is 123 kWh. At a =0.10, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H. Choose the correct answer below. O A. Ho: uS 930 H:u> 930 (claim) B. Ho: uS 890 H:p> 890 (claim) OC. Ho: u> 930 (claim) O D. Ho: u= 930 H u# 930 (claim) H:us 930 O E. Ho: u= 890 (claim) OF Ho: u>890 (claim) Hus 890 H:u#890 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical value is 1.28. O B. The critical values are t. Identify the rejection region(s). Select the correct choice below. O A. The rejection regions are…
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