A light bulb manufacturer guarantees that the mean life of a certain type of light bulb is at least 761 hours. A randomsample of 23 light bulbs has a mean life of 748 hours. Assume the population is normally distributed and thepopulation standard deviation is 60 hours. At a = 0.02, do you have enough evidence to reject the manufacturer'sclaim? Complete parts (a) through (e).(a) Identify the null hypothesis and alternative hypothesis.OA. Ho: 2761 (claim)Ha: H <761OD. Ho: <748 (claim)Ημ2748OB. Ho: >761Ha: HS761 (claim)O E. Ho: #761(claim)H₂=761OC. Ho: H=748Ha: #748 (claim)OF. Ho: μ≤748H₂: >748 (claim)

Answered: Image /qna-images/answer/bcec4932-b97a-46e9-9fa7-0b5c82060b5a.jpg

Answered: type A random guarantees that the mean…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A nutritionist claims that the mean tuna consumption by a person is 3.4 pounds per year. A sample of 90 people shows that the mean tuna consumption by a person is 3.3 pounds per year. Assume the population standard deviation is 1.02 pounds. At α=0.03, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. A. H0: μ=3.4 Ha: μ≠3.4 Your answer is correct. B. H0: μ>3.4 Ha: μ≤3.4 C. H0: μ≤3.3 Ha: μ>3.3 D. H0: μ≤3.4 Ha: μ>3.4 E. H0: μ>3.3 Ha: μ≤3.3 F. H0: μ≠3.3 Ha: μ=3.3 (b) Identify the standardized test statistic. z=negative 1.34−1.34 (Round to two decimal places as needed.)
nutritionist claims that the mean tuna consumption by a person is 3.4 pounds per year. A sample of 90 people shows that the mean tuna consumption by a person is 3.3 pounds per year. Assume the population standard deviation is 1.02 pounds. At α=0.03, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. A. H0: μ=3.4 Ha: μ≠3.4 Your answer is correct. B. H0: μ>3.4 Ha: μ≤3.4 C. H0: μ≤3.3 Ha: μ>3.3 D. H0: μ≤3.4 Ha: μ>3.4 E. H0: μ>3.3 Ha: μ≤3.3 F. H0: μ≠3.3 Ha: μ=3.3 (b) Identify the standardized test statistic. z=negative 0.93−0.93 (Round to two decimal places as needed.) (c) Find the P-value. 0.3520.352 (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis.
Testing:H0:μ=11.925H1:μ>11.925Your sample consists of 45 subjects, with a mean of 13.4 and standard deviation of 4.55.Calculate the test statistic, rounded to 2 decimal places. t=
T3.6
15
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