Many people believe that the average number of Facebook friends is 120. The population standard deviation is 39.2. A random sample of 47 high schoolstudents in a particular county revealed that the average number of Facebook friends was 145. At a = 0.01, is there sufficient evidence to conclude that themean number of friends is greater than 120?Part 1 of 5State the hypotheses and identify the claim with the correct hypothesis.Hoμ = 120H₁>120 claimThis hypotheses test is a one-tailedPart: 1 / 5not claim ▼Part 2 of 5▼test.Find the critical value(s). Round the answer to two decimal places. If there is more than one critical value, separate them with commas.Critical value(s):XS

Given Sample size n=47, sample mean x̄=145, standard deviations σ=39.2, level of significance…

Answered: Many people believe that the average…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a study of 110 women and 116 men, it was found that mean body temperature for women was 97.690 F and mean body temperature for men was 97.450 F. Assume that the populations are independent, and the standard deviations were found to to be 0.89o F for women, and 0.660 F for men. Use an α = 0.05 significance level to test the claim that woman and men have different mean body temperatures. For full credit your hypothesis test must include: the claim, the null and alternate hypothesis, your test statistic and corresponding p-value, your decision, and the interpretation of your decision as it relates to the claim. It is acceptable to use technology to calculate the test statistic and the p-value here.
CNNBC recently reported that the mean annual cost of auto insurance is 1006 dollars. Assume the standard deviation is 184 dollars. You will use a simple random sample of 88 auto insurance policies.Find the probability that a single randomly selected policy has a mean value between 980.5 and 1051.1 dollars.P(980.5 < X < 1051.1) = Part 2 Find the probability that a random sample of size n=88n=88 has a mean value between 980.5 and 1051.1 dollars.P(980.5 < M < 1051.1) =
The mean of the commute time to work for a resident of a certain city is 27.3 minutes. Assume that the standard deviation of the commute time is 7.1 minutes. What minimum percentage of commuters in the city has a commute time within 2.5 standard deviations of the mean? What are the commute times within 2.5 standard deviations of the mean?
The mean consumption of water per household in a city was 1239 cubic feet per month Due to a water shortage because of a drought, the city council campaigned for water use conservation by households. A few months after the campaign was started, the mean consumption of water for a sample of 92 househoids was found to be 1157 cubic feet per month. The population standard deviation is given to be 251 cubic feet a. Find the p-value for the hypothesis test that the mean consumption of water per household has decreased due to the campaipn by the city council. Would you reject the null hypothesis at a = 0.025? Round your answer to four decimal places. pvalue =i We b. Make the test of part a using the critical-value approach and a = 0.025. Round your answer for z to two decimal places. Zoberved We We conclude that the mean consumption of water per household has due to the campaign by the city council.
Suppose that IQ scores have a bell-shaped distribution with a mean of 101 and a standard deviation of 14. Using the empirical rule, what percentage of IQ scores are at least 115? Please do not round your answer.
The average number of calories from a fast food meal for adults in the US is 842 calories. A nutritionist believes that the average is higher than reported. They sampled 32 meals that adults ordered and found the sample mean to be 858 calories with a standard deviation of 49 calories. What are the null and alternative hypotheses?
The mean age when smokers first start is 13 years old with a population standard deviation of 1.8 years. A researcher thinks that smoking age has significantly changed since the invention of ENDS—electronic nicotine delivery systems. A survey of smokers of this generation was done to see if the mean age has changed. The sample of 34 smokers found that their mean starting age was 12 years old. Do the data support the claim at the 10% significance level?
The mean waiting time for non-emergency surgeries in your hospital is 87.5 days with astandard deviation of 14 days. Over the last year the hospital’s CEO has beenimplementing various programs to try to reduce the waiting time. You are asked to testwhether the wait times have changed from the previous average. Not knowing if thewait times have increased or decreased, you hypothesize that the wait times are not 87.5days. You randomly select 100 cases and calculate the average wait time, which is 84days. Use ?= 0.05
I will send the rest of question in a bit because of your guidelines
a Leche League International reports that the mean age of weaning a child from breastfeeding is age four to five worldwide. In America, most nursing mothers wean their children much earlier. Suppose a random survey is conducted of 21 U.S. mothers who recently weaned their children. The mean weaning age was 9 months (3/4 year) with a standard deviation of 2 months. Conduct a hypothesis test to determine if the mean weaning age in the U.S. is less than four years old. Conduct a hypothesis test at the 5% level. a. What is the p-value? (Round your answer to four decimal places.) b. What is the test statistic
A tire company claims that the lifetimes of its tires average 50,000 miles. The standard deviation of tire lifetimes is known to be 5,261 miles. You sample 100 tires and will test the hypothesis that the mean tire lifetime is at least 50,000 miles against the alternative that it is less. Assume, in fact, that the true mean lifetime is 49,545 miles. It is decided to reject Ho if the sample mean is less than 48,894. Find the level and power of this test. 0 Round your answers to four decimal places. Level of the test = Power of the test =

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