**Hypothesis Testing of Mean Monthly Residential Electricity Consumption**A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kilowatt-hours (kWh). To test the validity of this claim, you analyze a random sample of 64 residential customers, which results in a mean monthly consumption of 900 kWh. Assuming the population standard deviation is 129 kWh, the question is whether this data supports the company's claim at a significance level of \( \alpha = 0.01 \). The tasks involve completing parts (a) through (e).### Hypotheses:- **Null Hypothesis (\( H_0 \))**: \( \mu \leq 870 \) - **Alternative Hypothesis (\( H_a \))**: \( \mu > 900 \) (the claim)### Part (b): Critical Value and Rejection Region**Objective**: Find the critical value(s) and identify the rejection region(s). 1. **Critical Value**: - Provided answer: **2.33**2. **Rejection Region Identification**: - Options: - **A.** The rejection region is \( z \le -2.33 \). - **B.** The rejection region is \( z \ge 2.33 \). - **C.** The rejection regions are \( z \le -2.33 \) and \( z \ge 2.33 \). - Correct Choice: **B. The rejection region is \( z \ge 2.33 \).**The rejection region indicates the range of values for which the null hypothesis can be rejected.Make sure to follow these steps when conducting hypothesis testing, and use statistical software or technology as needed for precise calculations.

The null and alternative hypotheses are: Ho: \mu = 870μ=870 Ha: \mu > 870μ>870 This…

A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 64 residenti mean monthly consumption of 900 kWh. Assume the population standard deviation is 129 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). H, us 870 H, p> 900 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology (Round to two decimal places as needed.) A The critical value is 2.33 O B. The critical values are Identify the rejection region(s). Select the correct choice below. O A. The rejection region is z> 2.33. O B. The rejection region is z< 2.33. O C. The rejection regions are z< -2.33 and z>2,33.

A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 64 residenti mean monthly consumption of 900 kWh. Assume the population standard deviation is 129 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). H, us 870 H, p> 900 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology (Round to two decimal places as needed.) A The critical value is 2.33 O B. The critical values are Identify the rejection region(s). Select the correct choice below. O A. The rejection region is z> 2.33. O B. The rejection region is z< 2.33. O C. The rejection regions are z< -2.33 and z>2,33.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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