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Twenty-three milligrams of glucose were eaten by the bacteria Sanacoccus pumasareus. Calculate t amount of ATP your patient can generate under fermentative metabolism with this amount of glu Glucose MW-180.16 g/mole; 1 mole= 6.02 x 1023 molecules (Avogadro's number)). 2.8 x 10^21 ATPs 01.5 x 10^20 ATPs O 1.5 x 10^21 ATPs O2.8 x 10^20 ATPs O No ATP produced since it's fermentation O Lacks information, cannot be determined

Twenty-three milligrams of glucose were eaten by the bacteria Sanacoccus pumasareus. Calculate t amount of ATP your patient can generate under fermentative metabolism with this amount of glu Glucose MW-180.16 g/mole; 1 mole= 6.02 x 1023 molecules (Avogadro's number)). 2.8 x 10^21 ATPs 01.5 x 10^20 ATPs O 1.5 x 10^21 ATPs O2.8 x 10^20 ATPs O No ATP produced since it's fermentation O Lacks information, cannot be determined

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Twenty-three milligrams of glucose were eaten by the bacteria Sanacoccus pumasareus. Calculate the hypothetical amount of ATP your patient can generate under fermentative metabolism with this amount of glucose. (Note: Glucose MW-180.16 g/mole; 1 mole= 6.02 x 1023 molecules (Avogadro's number)). O2.8 x 10^21 ATPs 01.5 x 10 20 ATPs 01.5 x 10^21 ATPs O2.8 x 10^20 ATPs O No ATP produced since it's fermentation O Lacks information, cannot be determined Nexte Previous
Transcribed Image Text:Twenty-three milligrams of glucose were eaten by the bacteria Sanacoccus pumasareus. Calculate the hypothetical amount of ATP your patient can generate under fermentative metabolism with this amount of glucose. (Note: Glucose MW-180.16 g/mole; 1 mole= 6.02 x 1023 molecules (Avogadro's number)). O2.8 x 10^21 ATPs 01.5 x 10 20 ATPs 01.5 x 10^21 ATPs O2.8 x 10^20 ATPs O No ATP produced since it's fermentation O Lacks information, cannot be determined Nexte Previous
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