The superintendent of Hospital 2 performed the Goodness of Fit Test to test whether 25% of the patients go to Hospital 1, 15% of the patients go to Hospital 2 and 60% of the patients go to Hospital 3. Given: The superintendent found that the pp-value for the test is 0.25091 Let: p1=p1= be the proportion of patients at Hospital 1 p2=p2= be the proportion of patients at Hospital 2 p3=p3= be the proportion of patients at Hospital 3 a) Give the null hypothesis (select one from the options): H0:p1≠0.25,p2≠0.15,p3≠0.6 H0:p1=p2=p3=0 H0:p1=p2=p3=0.333 H0:p1=p2=p3 H0:p1=p2=p3=0.5 H0:p1≠p2≠p3 H0:p1=p2=p3=1 H0:p1=0.25,p2=0.15,p3=0.6 b) Calculate the value of the test statistic. ___________ c) The smallest level of significance, at which H0H0 may be rejected is (select one from the options): α=0.005 α=0.01 α=0.025 α=0.05 α=0.1 H0 cannot be rejected at any of the above levels of significance
A cross-sectional study is conducted to investigate cardiovascular disease (CVD) risk factors among a sample of patients seeking medical care at one of three local hospitals. A total of 500500 patients are enrolled. Based on the following data, we would like to determine if there is a significant association between the family history of CVD and the enrollment site.
Enrollment Site | ||||
Family History of CVD | Hospital 1 | Hospital 2 | Hospital 3 | Total |
Yes | 34 | 8 | 58 | 100 |
No | 104 | 72 | 224 | 400 |
Total | 138 | 80 | 282 | 500 |
- Given:
- The value of the test statistic is χ2= 6.912
- Use α=0.1 as the level of significance.
The superintendent of Hospital 2 performed the Goodness of Fit Test to test whether 25% of the patients go to Hospital 1, 15% of the patients go to Hospital 2 and 60% of the patients go to Hospital 3.
- Given: The superintendent found that the pp-value for the test is 0.25091
- Let:
p1=p1= be the proportion of patients at Hospital 1 |
p2=p2= be the proportion of patients at Hospital 2 |
p3=p3= be the proportion of patients at Hospital 3 |
a) Give the null hypothesis (select one from the options):
- H0:p1≠0.25,p2≠0.15,p3≠0.6
- H0:p1=p2=p3=0
- H0:p1=p2=p3=0.333
- H0:p1=p2=p3
- H0:p1=p2=p3=0.5
- H0:p1≠p2≠p3
- H0:p1=p2=p3=1
- H0:p1=0.25,p2=0.15,p3=0.6
b) Calculate the value of the test statistic.
___________
c) The smallest level of significance, at which H0H0 may be rejected is (select one from the options):
- α=0.005
- α=0.01
- α=0.025
- α=0.05
- α=0.1
- H0 cannot be rejected at any of the above levels of significance
Step by step
Solved in 4 steps