The spacing between two adjacent lines in the pure rotational spectrum of a diatomic molecule is 20.0 cm ¹. Given KBT = 200 cm-¹ -1 (at a specific temperature), calculate the relative population of the J-6 level O 1.6 O 3.8 O 2.7 O 2.4
The spacing between two adjacent lines in the pure rotational spectrum of a diatomic molecule is 20.0 cm ¹. Given KBT = 200 cm-¹ -1 (at a specific temperature), calculate the relative population of the J-6 level O 1.6 O 3.8 O 2.7 O 2.4
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Transcribed Image Text:The spacing between two adjacent lines in
the pure rotational spectrum of a diatomic
molecule is 20.0 cm ¹. Given KBT = 200 cm-¹
(at a specific temperature), calculate the
relative population of the J-6 level
O 1.6
O 3.8
O 2.7
O 2.4
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