The k of water is 1.86 kg °C/mol, approximately 4x the value of k,. If you attempted to freeze your 1.3m solution, how do you think the freezing point of water would be impacted?
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- Freezing point depression is a colligative property and it is noticed in solution when solute molecules are introduced into a solvent.
- The freezing point of solutions is all lower than that of a pure solvent and it is directly proportional to the molality of a solute.
- For example, when salt is added to the water, the water gets frozen before its freezing point and thus it gets depressed.
- Salt water has a lower vapor pressure than water.
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- How many grams of NaOH would you need to make 3,982 mL of a 3 M NAOH solution (m.w. = 40.00 g/mol)? Report your answer in the requested units to the nearest 2 decimal places (Example "40.02"). Do not report the units in your answer; enter the numbers only. It is recommended that you do not round between calculation steps.When 0.5 mol of a certain ionic substance is dissolved in 1.0 kg of water, the freezing point of the resulting solution is -2.8 °C (270.35 K), How many ions does the substance give when it dissolves?Solution A is 20 degrees celsius, Solution B is 80 degrees celsius (both are the same kind of solution). The goal is to make a 50 degree celsius solution; How much of solution A do you need (starting with 100g of solution B)? (cp=4.184 J/g C)
- A 35 mL of solution of hydrochloric acid is neutralized by 15 mL of 0.5 M potassium hydroxide. What is the concentration of hydrochloric acid? The balanced equation is HCI + KOH - H,O + KCI O 0.75 M O 0.25 M O 0.214 M O 0.786 MHow many grams of NaOH would you need to make 7,252 mL of a 230 mM NaOH solution (m.w. = 40.00 g/mol)? Do not include units in your answer; report your answer in the requested units.The concentration of a certain sodium hydroxide solution was determined by using the solution to titrate a sample of potassium hydrogen phthalate (abbreviated as KHP). KHP is an acid with one acidic hydrogen and a molar mass of 204.22 g/mol. In the titration, 58.23 mL of the sodium hydroxide solution was required to react with 0.3520 g KHP. Calculate the molarity of the sodium hydroxide. Molarity = __________ M
- How many grams of NaCl are required to prepare 100 mL of a solution of 1 M NaCl? (NaCl molecular weight = 58.44 g/mol)Calculate the molarity (M) of a 46% (w/v) copper sulfate solution (m.w. = 160.0 g/mol).If your 16x concentrated stock solution contains 20g of NaCl per liter, how much Nacl would one liter of your working solution contain? Round your result to 2 decimal points. g of Nacl
- You are given a solution of 0.117 M NaOH solution. You need to neutralize 10.00 mL of the NaOH solution with an acid called KHP. The reaction is: KHP+ NaOH --> H2O + a salt If you are going to make up a KHP stock solution in a 100.00 mL Volumetric flask and use 14.137 mL of the KHP stock solution to neutralize the NaOH, what mass of KHP would you need to use? The molar mass of KHP is 204.22 g/moleA solution of an unknown carbohydrate gave the following optical readings when analyzed by a polarimeter +3.24, +3.15, +3.30, +3.20, 43.21, +3.19, +3.17, +3.23, +3.20, +3.25. (a) Calculate the sample mean. 1.80.00 mL of 0.350 M benzoic acid (K = 6.4×105) is titrated by 0.350 M NaOH. Calculate the pH of the acid solution before any titrant is added. PH Calculate the pH after 58.9 mL of 0.350 M NaOH is added to 80.00 mL of 0.350 M benzoic acid. pH = Calculate the pH after 80.00 mL of 0.350 M NaOH is added to 80.00 mL of 0.350 M benzoic ad pH = Calculate the pH after 110 mL of 0.350 M NaOH is added to 80.00 mL of 0.350 M benzoic acid. pH=