A chemist prepares a solution of aluminum sulfite (Al, (SO,).) by measuring out 179. µmol of aluminum sulfite into a 300. mL volumetric flaskand filling the flask to the mark with water.Calculate the concentration in mmol/L of the chemist's aluminum sulfite solution. Be sure your answer has the correct number of significantdigits.mmolx10

Molarity It is defined as the number of moles of a substance dissolved in 1 litre of a solution.…

Answered: alculate the concentration in mmol/L of…

alculate the concentration in mmol/L of the chemist's aluminum sulfite solution. Be sure your answer has the correct number of significant igits.

Principles Of Pharmacology Med Assist

6th Edition

ISBN:9781337512442

Author:RICE

Publisher:RICE

Chapter1: Numerals And Fractions

Section: Chapter Questions

Problem 3RP

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Question

A chemist prepares a solution of aluminum sulfite (Al, (SO,).) by measuring out 179. µmol of aluminum sulfite into a 300. mL volumetric flask
and filling the flask to the mark with water.
Calculate the concentration in mmol/L of the chemist's aluminum sulfite solution. Be sure your answer has the correct number of significant
digits.
mmol
x10

Expert Solution

Step 1Introduction

Molarity

It is defined as the number of moles of a substance dissolved in 1 litre of a solution.
It is used to describe the concentration of a solution.

Moles:

$N u m b e r o f m o l e s = W e i g h t i n g r a m s / M o l e c u l a r W e i g h t$

Step 2 Interpretation of information given in the question

According to the question

A chemist prepares a solution of Aluminum sulfite solution by dissolving 179 µmoles of Aluminum sulfite in 300 ml of water.
179 µmoles is equal to 0.000179 moles or 0.179 mmoles
$W e i g h t i n g r a m s = N u m b e r o f m o l e s * M o l e c u l a r W e i g h t = 0.000179 * 342.15 = 0.0612 g m s / 300 m l o f w a t e r$
It means the chemist has dissolved 0.0612 grams of Aluminum sulfite in 300 ml of water.

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