The given data sohws a sieve analysis of a soild sample. Classify the soild using AASHTO Method. Sieve No.     Diameter (mm)     Percent Passing   No. 4                4.760                         96   No. 8                2.380                         80   No. 10              2.000                         78   No.20               0.840                         61   No.40               0.420                         56

Q: the soil using USCS for the data given: Sieve Size 4.75 mm, weight retained 20 g; Sieve Size 0.075…

A: Given data-  LL = 40 PL = 18  weight retained 730 g 1000 g of soil was used.

Q: Q1: Classify the below soil according to Unified Soil Classification System (USCS) and .the AASHTO…

A: The fines proportion of the given soil is 10%. So, the proportion of the fine is more than 5% and…

Q: For a given sieve analysis: No.4 - % finer is 94, for No 200 - %finer 3. Cu=4.48 Cc=1.22. Classify…

A:

Q: A Classify the soil samples shown below using AASHTO and USCS systems: Sieve No. 4 10 20 40 60 100…

A: Following is required answer :

Q: e results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760…

A:

Q: The sieve analysis of ten soils and the liquid and plastic limits of the fraction pass- ing through…

A: “Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: In the dry sieve analysis of soil the sieves are placed as sequential order one below the other as:…

A: Sieve analysis deals with the method for the determination of grain size distribution in soils. An…

Q: Classify the following soil using both USCS and AASHTO systems. (SHOW ALL YOUR WORK). LL = 63%, and…

A: Given:- The percent passing through the different sieves of soil is given The liquid limit of the…

Q: Sieve Soil A Soil B 3/4 in. 100 3/8 in 95 No. 4 85 --- 100 75 16 94 63 30 70 51

A: Data given Sieve Sieve size (mm) Percentage Finer Soil A Soil B 3/4 in 19   100 3/8 in 9.5…

Q: A Sample of soil was tested in the laboratory with the following results Liquid limit =30% Plastic…

A: we have Liquid limit =30% Plastic limit =12%   U.S. Sieve Size                  Percentage Passing…

Q: 39. The following table shows a data set from a sieve analysis. (a) Complete the rest of the table.…

A:

Q: The following data was obtained from sieve analysis test Sieve No. Sieve Mass of Mass of sieve empty…

A: sieve no sieve opening mass of mpty sieve mass of sieve + retained mass retained on sieve %      4…

Q: Yren wan given a sol sample which yelds the totowing passing percentage tor derent sieves Seve No.…

A: Solution: AASHTO System GI

Q: For a given sieve analyis: No. 4 - % finer 92%, for No. 200 -%finer 48. LL=30, PL= 8. Classify the…

A: Classify the soil using USCS.

Q: Problem 2 Classify the soil using USCS system. Give the group symbols and group names. Soil Sieve…

A: For soil 'e' (I) since % finer #200 is 11% , So the soil is course grained soil. (II) as % finer #4…

Q: Q1: Classify the below soil according to Unified Soil Classification System (USCS) and the AASHTO…

A: The percentage of the soil passing through the 75μ sieve is 10%. So, the symbol for the soil has two…

Q: For a given sieve analyis: No. 4 - % finer 100%, for No. 200 -%finer 86. LL=55, PL= 28. Classify the…

A:

Q: estion 41 The given datashows a sieve analysis of a soil sample. Classify the soil using AASHTO…

A: The soil sample that has been collected from site must be classified so that designing of foundation…

Q: a. Computation must be complete. Problem SOIL TESTING SUMMARY SAMPLE SIEVE NUMBER 10 30 40 60 100…

A: Solution: Solution: a. 1. %retained on the #200 (R200) =14.28 % retained on the #4 (R4)=100, As it's…

Q: Question 38 Yiren was given a soil sample which yields the following passing percentage for…

A:

Q: lable 5.2 Unified Soll Classification System (Based on Material Passing 76-2-mm Sieve) Criteria for…

A: Passing from sieve 200 =17% Passing from sieve 4=100%  it means sieve belongs to sand  fines are…

Q: B. ( A Soil Specimen has the following characteristics. % passing No.4 sieve = 85 % passing No.200…

A: Given, LL = 36% PL = 31%

Q: eve No. Diameter Soil A 4 4.760 89 6 2.380 70 10 2.000 63 20 0.840 55 40 0.420 40 60 0.250 31 100

A: Step1:Look at the % passing through sieve no 200=4<50%⇒COARSE GRAINED SOIL

Q: General classification Granular materials (35% or less of total sample passing No. 200) A-1 A-2…

A: To Determine Group index of the given soil. Given Percentage Passing through each seive size of the…

Q: Percent Passing (by weight) You are provided the mechanical sieve/hydrometer and Atterberg Limit…

A: Given: Soil LL PL 1 68 19 2 39 31 3 NA NA To find: The soil classification with the…

Q: GEOTECHNICAL ENGINEERING: The resuts of a sieve analysis for a soil sample are given in the table.…

A: The data given is:  Cc = 2 Cu = 6 LL = 20 PL = 14 % passing through 4.75 mm sieve = 95 % passing…

Q: III -"Particle Size Distribution Test" Tabulation of Data: 1 4 7 Sieve Sieve Mass Mass of Mass of…

A:

Q: Usual types of significant Stone fragments, gravel, and sand Fine Silty or clayey gravel and sand…

A: To Determine Soil classification according to AASHTO soil classification system. Given Sieve number.…

Q: 3. Classify the following soils using the Unified Soil Classification System. Give group symbols and…

A:

Q: A Sample of soil was tested in the laboratory, and the test results were listed as follows. Classify…

A:

Q: The size characteristics of the soil particles are shown in the table below. Classify soil using: 1.…

A: Given data size (mm) % finer 4.75 93 2 77 0.033 69 0.018 55 0.01 42 0.0062 33…

Q: Classify the soil using AASHTO. The liquid limit and plastic limit are found to be 30 and 20,…

A: iLook at the %passing through No 200 sieve :=20%<35% so Granular material

Q: Classify Soil D (group symbol and group name) using USCS method: SOIL SAMPLE SIEVE NO. DIA. (mm) A B…

A: Following is required classification for soil D :

Q: Classify Soils A and B as given in Example 9-1 and obtain the names. Assume Soil B to be inorganic.…

A: The soil is classified based on the composition of particle-like sand, gravel, clay or etc., Unified…

Q: 2. Prove n-e/(1+e) and e-n/(1-n) based on definitions of void ratio and porosity.

A: This is a multiple-type question, as per policy we can solve only the first question(unless…

Q: Determine its classification using USCS   SP     GW     SW     GP     None of the above

A: Given, Sieve analysis data

Q: Answer ALL Questions Time: 2 Hours Q3: Classify the following soil by using the Unified soil…

A: given liquid limit= 60% and plastic limit =40% plasticity index=LL-PL Ip=LL-PLIp=60-40Ip=20%

Q: For a given sieve analyis: No. 4 - % finer 100%, for No. 200 -%finer 45. LL=36, PL= 22. Classify the…

A:

Q: Determine its classification using USCS.

A: GEO TECHNICAL ENGINEERING- SOIL CLASSIFICATION

Q: Using the Unified Soil Classification System classify the following three soils: Sieve size Soil 1…

A: Solution: The unified soil classification depends on the percentage of soil passing through NO. 200…

Q: General classification Granular materials (35% or less of total sample passing No. 200) A-2 A-1…

A: iLook at % passing through No 200 sieve =60%>35%so silt-clay

Soil classification and characteristics

Soil classification is a method of categorizing soil based on its properties, types, and uses. The motive of soil classification is to arrange various types of soils and divide them into groups for various engineering and agricultural purposes. Soil classification is carried out by various agencies as per their purposes. From an engineering perspective, soil classification is done to find out the suitability of soil for various construction purposes like the construction of dams, foundations, highways, infrastructures, and so on. For engineering purposes, the soil is classified by the following systems: