Answer ALL QuestionsTime: 2 HoursQ3: Classify the following soil by using the Unified soil classification system. Give thegroup symbols and the group names.Table 1. Sample 1 Grain Size Results(ASTM D422).Table 2. Atterberg Limits Results(ASTM D4318).Sleve No. Dia. (mm) % PassingSamplePLLL% in12.7100G040144.7597#10294#200.8584# 400.42557#600.25321400.10615#2000.07510090Atterberg Limit Results:LL = 60%, PL = 40%E 80* 70-60 -504030-a 20101 30 a40100 0.120010800.01Particle Diameter (mm)Answer ALL QuestionsTime: 2 Hours70CHorOH60A-line PI = 0.73(LL - 20)Or504030CLMHOL20orCL-MLOHML10 -orOL10 16 20 3040 5060 70 8090 100Liquid limitFigure 5.3 Plasticity chartPercent (%) Finer by WeightPlasticity indexU-line PI = 0.(LL - 8)O Cengage Learning 2014

given liquid limit= 60% and plastic limit =40% plasticity index=LL-PL Ip=LL-PLIp=60-40Ip=20%

Answer ALL Questions Time: 2 Hours Q3: Classify the following soil by using the Unified soil classification system. Give the group symbols and the group names. Table 1. Sample 1 Grain Size Aesults (ASTM D422). Table 2. Atterberg Limits Results (ASTM D4318). Sleve No. Dia. (mm) % Passing Sample LL PL % in 12.7 100 60 40 14 4.75 97 #10 2 94 #20 0.85 84 #40 0.425 57 #60 0.25 32 #140 0.106 15 #200 0.075

Answer ALL Questions Time: 2 Hours Q3: Classify the following soil by using the Unified soil classification system. Give the group symbols and the group names. Table 1. Sample 1 Grain Size Aesults (ASTM D422). Table 2. Atterberg Limits Results (ASTM D4318). Sleve No. Dia. (mm) % Passing Sample LL PL % in 12.7 100 60 40 14 4.75 97 #10 2 94 #20 0.85 84 #40 0.425 57 #60 0.25 32 #140 0.106 15 #200 0.075

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: • AASHTO SOIL CLASSIFICATION (by AASHTO) AASHTO = American Association of state Highway and…

A: Group Index of soil is the number used to allude to the nature of soil utilized as subgrade material…

Q: Problem 1 The following grain size distribution test results were obtained from sieve analysis test.…

A: GIVEN U.S Sieve number and percentage Passing through each seive size. LL = 23, PL = 19 To…

Q: • Problem 1 - Classify the soil to be used as a highway subgrade material using AASHTO…

A: The given system classify the soil based on the value of liquid limit, plastic limit and the…

Q: Required only: #7, #9, and #12

Q: A Sample of soil was tested in the laboratory with the following results Liquid limit =30% Plastic…

A: we have Liquid limit =30% Plastic limit =12% U.S. Sieve Size Percentage Passing…

Q: Classify the soil according to ASTM-CS

A: The soil is classified into fine-grain soil or coarse grain soil based on the soil passing through…

Q: Classify the given soils using the Unified Soil Classification System (USCS). Give the group symbols…

Q: Soil samples collected from the field gave the following laboratory test results: • Percentage…

Q: a)Determine the coefficients of uniformity, Cu and curvature Cc for soils A, B, and C. (Done in…

Q: Classify the following soil using the U.S. Department of Agriculture (USDA) textural classification…

A: Given , We have total 5 types of soil samples i.e A, B, C, D,and E. We have to classify the each…

Q: Classify the following soils by USCS classification system. Percent finer than (sieve analysis) No.…

A: For the Soil 1, The percentage finer than sieve number 4 is 71%. The percentage finer than sieve…

Q: The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and the…

Q: 2. Determine the Unified Soil Classification System (USCS) classification for the following…

A: Unified soil classification system(USCS): (1) Classify the soil whether it is coarse or fine grained…

Q: Question 22 A soil sample obtained from below the groundwater table has a moisture content of 23.3 %…

Q: 2.Determine the percentage of Gravel, Sand, Silt, and Clay and determine the value of Cu and Cc for…

Q: The soil is classified as using the AASHTO method (Ignore the group index)

Q: | Laboratory testing was performed on two soil samples (A and B). (a) Determine the USCS…

A: Note: We'll answer the first question since the exact one wasn't mentioned. Please resubmit a new…

Q: Classify the following soils by using the Unified Soil Classification System. Give the group symbols…

A: The USCS classification chart is shown below:

Q: Given the test results that follow, classify the soil in both the Unified Soil Classification System…

A: Given:- The test result of the soil sample is given The percent passing through No. 4 sieve = 48…

Concept explainers

Soil classification and characteristics

Soil classification is a method of categorizing soil based on its properties, types, and uses. The motive of soil classification is to arrange various types of soils and divide them into groups for various engineering and agricultural purposes. Soil classification is carried out by various agencies as per their purposes. From an engineering perspective, soil classification is done to find out the suitability of soil for various construction purposes like the construction of dams, foundations, highways, infrastructures, and so on. For engineering purposes, the soil is classified by the following systems:

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

• Problem 1- . Classify the soil to be used as a highway subgrade material using AASHTO classification system; Sieve No. No. 4 No. 10 No. 20 No. 40 No. 60 No. 140 No. 200 Size opening (mm) 4.75 2.00 0.850 0.425 0.250 0.140 0.075 % Finer 100 92 84 69 50 40 37 Liquid limit for soil passing # 40 sieve was determine to be 40% and plasticity index was 20%.
Problem D: For problems 14 to 17. Classify the following soils by the AASHTO classification System. Description A D Percent finerthan No. 4 sieve 100 | 92 100 94 Percent finerthan No. 10 sieve 100 85 80 80 Percent finerthan No. 40 sieve 96 71 78 51 Percent finerthan No. 200 sieve 72 56 59 15 Liquid Limit Plasticity Index 16) Soil A is ? 58 35 42 26 23 19 13 12 a) A-7-5(19) b) A-2-6 (0) c) A-7-6 (18) d) A-7-5 (18) 17) Soil Bis ? a) A-6(13) b) A-7-5(0) c) A-6 (7) d) A-6 (8) 18) Soil Cis ? a) A-7-6(5) 19) Soil D is ? a) A-2-6(2) b) A-7-6 (8) c) A-7-6 (7) d) A-7-6(6) b) A-3 (0) c) A-2-6 (0) d) A-2-6 (2)
For a soil specimen, given the following: % passing sieve #4-92 %, sieve #10 -81%, sieve # 40-78%, LL-48%, PL-16%, GI-18.2 classify the soil by AASHTO classification system. GI = (F200-35)[0.2 + 0.005 (LL - 40)] +0.01 (F20015)(PI – 10)
A sample of soil was tested in the laboratory, and the test results were listed as follows. Classify the soil by both the AASHTO and the USCS. - LL = 29%, PL = 19% Sieve Size 1 in 3/4 in 3/8 in #4 #10 #40 #200 Percent Passing 100 90 82 70 65 54 25
The table below shows the laboratory results of the sieve analysis of a sample. The soil has a liquid limit of 35% and plasticity limit of 9%. Determine the following: a) Plot the grain size curve. b) Classify the soil according to SIZE (mm) WEIGHT RETAINED (gms.) 0.25 18.96 USCS 0.149 33.18 c) Classify the soil according to 0.074 45.03 AASHTO 0.052 54.51 d) Classify the soil according to 0.02 42.66 USDA 0.01 11.85 0.004 4.74 0.001 4.74 PAN 21.33 Page 1 | 1 Q + -