Problem 1 The following grain size distribution test results were obtained from sieve analysis test. Percent Passing U.S. Sieve Number 4 100 10 20 90 64 40 38 80 200 18 13 Also, the Atterberg test results revealed the following results LL = 23 and PL = 19 Classify the soil by using a) AASHTO soil classification system b) USCS soil classification system Give group names and group symbols. Show the GSDC and sketch of finding necessary information from GSDC.

Problem 1 The following grain size distribution test results were obtained from sieve analysis test. Percent Passing U.S. Sieve Number 4 100 10 20 90 64 40 38 80 200 18 13 Also, the Atterberg test results revealed the following results LL = 23 and PL = 19 Classify the soil by using a) AASHTO soil classification system b) USCS soil classification system Give group names and group symbols. Show the GSDC and sketch of finding necessary information from GSDC.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Show your complete solution so I can follow thanks
Classify the following soils by the AASHTO classification system. Give the group index for each soil.
Thank u
18. The results for sieve analysis is shown in the following table: Sieve No. 4 10 20 40 60 100 200 % Passing 69.3 59.1 48.3 38.5 28.4 19.8 4.5 Liquid Limit Plastic Limit Non-Plastic (NP) Non-Plastic (NP) a. Determine the classification of soil according to AASHTO. b. Determine the classification of soil according to USCS.
SITUATION 9 The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
Question 2 The sieve analysis of soil and the liquid and plastic limits of the fraction passing through the No. 40 sieve are given below. Classify the soils using the AASHTO classification system and give the group indexes. % Passing No. 10: 87 % Passing No. 40: 62 % Passing No. 200: 30 LL = 32 PL = 24 Group classification: Blank 1 Group index: Blank 2
47.) The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 89 6 2.380 70 10 2.000 63 20 0.840 55 40 0.420 31 60 0.250 20 100 0.149 18 200 0.074 4 LL 60 PL 40 Determine its classification using USCS. GW SP None of the above SW GP
Given the sieve analysis and plasticity data for five soils, classify the 5 soils according to Unified Soil Classification System (USCS) and AASHTO soil classification system. Explain your steps for each soil sample classifications.
Classify the soil sample using USDA Textural Classification System if the sample has the following particle size distribution. Gravel = 18 % Silt = 11 % Sand = 66 % Clay = 5 % O Loamy Sand O sity Loam O Sandy Loam O sity Clay
The following table shows the sieve analysis data on the left and hydrometer test data on the right for the minus No. 200 sieve material for a given soil. (a) Compute Cu and Cc. (b) Report the percentage gravel, sand, silt, and clay according to AASHTO. (c) Classify the soil according to AASHTO.
Within few minutes
4. Determine the USCS designation and soil description of a soil sample given the following sieve analysis test results: D10 = 0.2 mm = D30 0.73 mm D60 3.35 mm % passing #4 = 77.5 % passing #200 = 9.5 The fines are silty.