Direction:a. Computation must be complete.ProblemSOIL TESTING SUMMARYSAMPLESIEVE NUMBER10304060VALUES OF Deo, Dio, and DidPARAMETERDao (mm)Dec (mm)D₁ (mm)100120200PANexplain your answer.3.% RETAINED010.31119.447.86.414.89.8SAMPLE No. 10.2110.1460.076LL61PLREQUIRED:a. Classify the soil using Unified Soil Classification System (USCS)1What is the main type of the soll?2is the soll sample above or below the A-Line? Aside from using the plasticity chart,What is the group symbol of the soil?What is the group name of the soil?Provide plotting in the plasticity chart and flowchart in the solution.b. AASHTO. Provide Table and plasticity chart in the solution.52

Solution: Solution: a. 1. %retained on the #200 (R200) =14.28 % retained on the #4 (R4)=100, As it's…

a. Computation must be complete. Problem SOIL TESTING SUMMARY SAMPLE SIEVE NUMBER 10 30 40 60 100 120 200 PAN VALUES OF Deo, Dio, and Dic 1. 2. PARAMETER Dao (mm) Dia (mm) D₁ (mm) % RETAINED 0.1 0.3 1.1 19.4 explain your answer. 3. 47.8 6.4 14.8 9.8 SAMPLE No. 1 0.211 0.146 0.076 LL 61 REQUIRED: a. Classify the soil using Unified Sail Classification System (USCS) What is the main type of the soil? is the soil sample above or below the A-Line? Aside from using the plasticity chart, PL What is the group symbol of the soil? What is the group name of the soil? Provide plotting in the plasticity chart and flowchart in the solution. b. AASHTO. Provide Table and plasticity chart in the solution. 52

a. Computation must be complete. Problem SOIL TESTING SUMMARY SAMPLE SIEVE NUMBER 10 30 40 60 100 120 200 PAN VALUES OF Deo, Dio, and Dic 1. 2. PARAMETER Dao (mm) Dia (mm) D₁ (mm) % RETAINED 0.1 0.3 1.1 19.4 explain your answer. 3. 47.8 6.4 14.8 9.8 SAMPLE No. 1 0.211 0.146 0.076 LL 61 REQUIRED: a. Classify the soil using Unified Sail Classification System (USCS) What is the main type of the soil? is the soil sample above or below the A-Line? Aside from using the plasticity chart, PL What is the group symbol of the soil? What is the group name of the soil? Provide plotting in the plasticity chart and flowchart in the solution. b. AASHTO. Provide Table and plasticity chart in the solution. 52

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Q 02: (CLO2) (a) Sieve and hydrometer analysis for two soils are given in the following, calculate the amount of Gravel Sand and Clay according to AAHTO and Unified Soil Classification system for both soils. Also mention which soil is coarse soil in this case and why? Soil 1 Soil 2 Diameter or Sieve No. Mass Retained Diameter or Sieve No. Mass Retained (g) (g) % in ½ in # 4 % in ½ in # 4 15.48 #10 #10 61.92 112.23 49.80 Sieve # 20 #20 Analysis #40 # 40 #60 30.1 #60 51.10 #100 36.4 #100 50.31 # 200 23.1 27.0 19.23 Pan 290.3 Pan No hydrometer analysis Diameter (um) % Finer Hydrometer Analysis 45 10 61 42 37 1 27 (b) What is the difference between Clay and Clay sized non cohesive soils?
The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 89 6 2.380 70 10 2.000 63 20 0.840 55 40 0.420 40 60 0.250 31 100 0.149 20 200 0.074 4 LL 60 PL 40 Determine its classification using USCS.
Yiren was given a soil sample which yields the following passing percentage for different sieves. Sieve No. Diameter (mm) Percent Passing (%) No. 4 4.760 99 No. 8 2.380 85 No. 10 2.000 71 No. 20 0.840 65 No. 40 0.420 63 No. 60 0.250 55 No. 100 0.149 50 No. 200 0.074 32 Characteristics of Fraction Passing No. 40 LL = 41 PL = 16 What will be this soil's resulting group index?
Determine: 1. The coefficient of gradation 2. The uniformity coefficient 3. Sorting Coefficient Please answer this asap. For upvote. Thank you very much
Someone can help me with this please.
The results of the sieve analysis done on a soil are shown below Sieve No. Diameter Soil A 4 4.760 100 6 2.380 98 10 2.000 91 20 0.840 85 40 0.420 84 60 0.250 79 100 0.149 61 200 0.074 55 LL 61 PL 26 Determine its classification using USCS.
A The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58. The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by AASHTO system.Justify your answer. provide fbd a.A-6 (5) b.A-5 (6) c.A-4 (5) d.A-7-6 (20)
GEOTECHNICAL ENGINEERING: The resuts of a sieve analysis for a soil sample are given in the table. Cc = 2 and Cu = 6. If the LL and the PL of the soil sample are 20 and 14 respectively, classify the soil according to USCS classification. Sieve Opening (mm) % passing 4.75 95 0.075 65
soil ضهدتنس
III -"Particle Size Distribution Test" Tabulation of Data: 1 4 7 Sieve Sieve Mass Mass of Mass of Soil Percentage Cumulative Percent Number Size of each Sieve Retained-(Wn) on each percent Finer (mm) each + Retained sieve retained (%) Sieve Soil (Rn) (Σ Rn ) (3) 700 (g) 4 4.76 725 8 2.38 700 780 10 2.00 700 810 20 0.84 700 860 40 0.42 700 880 60 0.25 730 950 80 0.180 740 1120 100 0.149 750 1340 200 0.074 800 910 Pan 900 985 Plot the points of each sieve size between particle size and Percent finer. 100 90 80 70 50 40 20 10 0.000 0.001 0.010 0.100 1.000 10.000 Particle Size (mm) Particle Size Distribution Result Percentage Passing (%)
Question 44 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 99 No. 8 2.380 91 No. 10 2.000 90 No. 20 0.840 85 No. 40 0.420 81 No. 60 0.250 79 No. 100 0.150 67 No. 200 0.075 60 Characteristics of No. 40 Fraction LL 39 PL 32
Question 42 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 100 No. 8 2.380 88 No. 10 2.000 69 No. 20 0.840 61 No. 40 0.420 56 No. 60 0.250 43 No. 100 0.150 19 No. 200 0.075 9. Characteristics of No. 40 Fraction LL PL General classification Granular materials (35% or less of total sample passing No. 200) A-1 A-2 Group classification A-1-a A-1-b A-3 A-2-4 A-2-5 A-2-6 A-2-7 Sieve analysis (percent passing) No. 10 50 max. No. 40 No. 200 30 max. 15 max. 50 max. 25 max 51 min. 10 max. 35 max. 35 max. 35 max 35 max. Characteristics of fraction passing No. 40 Liquid limit. Plasticity index 40 max. 41 min. 40 max. 41 min. 6 max NP 10 max. 10 max. 11 min. 11 min. Usual types of significant constituent Stone fragments. gravel, and sand Fine Silty or clayey gravel and sand sand materials SUS F1 F2 F3 F4 FS F6 F7 F8 24 4 % & 5 R Y 因