SITUATION 4:The following data shows the results ofthe sieve analysis of two soil samplesA and B.SievePercentPassingBno.Opening(mm)A# 44.7690100#82.386498#102.05890# 25#600.71302272680.25#1000.1491065# 2000.074450LL6055PL102015359. Which of the following most nearlygives the uniformity coefficient for soilA.b. 15d. 8а. 12с. 1010. Find the Group Index of soil Ausing AASHTO systemа. 0с. 18b. 20d. 34

The uniformity coefficient (Cu) for a soil is given by, Cu=D60D10here,DD60: opening size…

Answered: The following data shows the results of…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 80 No. 8 2.380 71 No. 10 2.000 69 No. 20 0.840 63 No. 40 0.420 57 No. 60 0.250 43 No. 100 0.150 40 No. 200 0.075 39 Characteristics of No. 40 Fraction LL 36 PL 21 A. A-6(1) B. A-4(1) C. None of these. D. A-6(2) E. A-4(2)
Question 42 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 100 No. 8 2.380 88 No. 10 2.000 69 No. 20 0.840 61 No. 40 0.420 56 No. 60 0.250 43 No. 100 0.150 19 No. 200 0.075 9. Characteristics of No. 40 Fraction LL PL General classification Granular materials (35% or less of total sample passing No. 200) A-1 A-2 Group classification A-1-a A-1-b A-3 A-2-4 A-2-5 A-2-6 A-2-7 Sieve analysis (percent passing) No. 10 50 max. No. 40 No. 200 30 max. 15 max. 50 max. 25 max 51 min. 10 max. 35 max. 35 max. 35 max 35 max. Characteristics of fraction passing No. 40 Liquid limit. Plasticity index 40 max. 41 min. 40 max. 41 min. 6 max NP 10 max. 10 max. 11 min. 11 min. Usual types of significant constituent Stone fragments. gravel, and sand Fine Silty or clayey gravel and sand sand materials SUS F1 F2 F3 F4 FS F6 F7 F8 24 4 % & 5 R Y 因

EAM MAN TESİ MSKŪ-LMS Hydrometer and sieve analysis were conducted on a soil sample. amadı Find D10, D60, uniformity coefficient (Cu), coefficient of curvature (CC) considering the chart given below. erinden Hint: Cu=D60/D1o and CC=(D30)2 / (D10XD60) miş 100 90 80 70 60 50 40 30 20 10 SILT SAND GRAVEL 100 0,001 CLAY 0,1 10 0,01 DANE ÇAPI / PARTICLE SIZE (mm) D20: (in mm) Seς Seç. Cu 14.28 0.1 Deo: (in mm) 5.14 0.007 CC Consolidation test results are provided below, (Hint: C, or Ce = Ae/log(of/ai') ): nmadi zerinden nmiş AR 21 lenov GEÇEN DANE YÜZZDESİ / PERCENT FINER THAN D
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Sieve No. Diameter Soil A 4 4.760 96 8 2.380 80 10 2.000 78 20 0.840 61 40 0.420 56 60 0.250 48 100 0.150 39 200 0.075 33 Characteristics of No. 40 Fraction LL 46 PL 31
The result from the sieve analysis is shown: Calculate the coefficient of uniformity. Determine the percentage of sand? What is the effective size of the sample (in mm).
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Sieve No. Diameter Soil A 4 4.760 80 8 2.380 71 10 2.000 69 20 0.840 63 40 0.420 57 60 0.250 43 100 0.150 40 200 0.075 39 LL 36 PL 21
Determine the percentage of the following types of soil in the sample;
Problem The following are the results of a sieve analysis: a. Determine the percent finer than each sieve and plot a grain- size distribution curve. b. Determine D10, D30, and D60 from the grain-size distribution curve. c. Calculate the uniformity coefficient, C. the coefficient of gradation, Co. U.S. sieve no. 4 10 20 40 60 80 100 200 Pan Mass of soil retained (g) 0 44 56 82 51 106 92 85 35
Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 95 10 2.000 80 20 0.850 73 40 0.425 54 60 0.250 25 100 0.150 12 200 0.075 7 Pan --- 0 Determine the value of the coefficient of gradation/curvature. Round off to three decimal places.
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 100 No. 8 2.380 100 No. 10 2.000 95 No. 20 0.840 81 No. 40 0.420 74 No. 60 0.250 69 No. 100 0.150 55 No. 200 0.075 51 Characteristics of No. 40 Fraction LL 48 PL 40 A. A-5(3) B. A-7-5(4) C. None of these. D. A-5(4) E. A-7-6(3)
Soil mechanics سملن
QUESTION 2 a. The results given in Table 1 were obtained in a particle size distribution test for soil sample received in the laboratory. Table 1 US Sieve No. Size Opening(mm) Weight Retained(g) 4 4.75 0 10 2.0 18.5 20 0.85 53.2 40 0.425 90.5 60 0.25 81.8 100 0.150 92.2 200 0.075 58.5 Pan - 26.5i. Determine the percentage passing each sieve and plot the particle size distribution curve. ii. How much fine-grained soils are in the sample ? iii. Determine the amount of gravel and sand in the sample ? iv. Determine D10, D30, and D60 from the grain-size distribution curve. v. Calculate the uniformity coefficient, Cu. vi. Calculate the coefficient of gradation, Cc. vii. Describe the gradation curve (eg poorly graded)

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