Determine the Coefficient of Uniformity. A 7.64 x 10-1 B 7.78 x 10-1 7.92 (D) 7.67
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- dys.mu MSKÜ-LMS 016 ŞB: 1 ÖRGÜN Soil Mechanics Mühendislik Fakültesi Mac Atterberg limits of a soil sample are given: LL:55% and PL:25%. Give the name of the soil typle considering the chart given below? Remember PI=LL-PL 60 U-line PI - 0.9 (LL -8) 50 Z 40 CH or OH A-line PI0.73 (LL - 20) 30 CL OH 20 or OL MH CL- ML 10 ML& OL 10 20 30 40 50 60 70 80 90 100 Liquid limit (%) O a. CL or OL O b. CH OR OH O c. OH or ML O d. GL or ML O e. M ail E AR .ill lenovo Plasticity index (%)Find the value of Cc of the following soil data sample Weight Percentage Cumulative Percentage Sieve Weight retained (gm) percentage retained (C) retained finer S.NO Select one: O a. 10.85 size (gm) N = (100 - C) {W,/ W,} x 100 1 75mm 100 O b. 7.36 63mm 100 O c. 18.34 50mm 100 O d. 2,96 4 37.5mm 454 22.7 22.7 77.30 5 28mm 285 14.25 36.95 63.05 6 20mm 207 10.35 47.30 52.70 7 14mm 318 15.90 63.20 36.80 8 10mm 206 10.30 73.50 26.50 6.3mm 118 5.90 79.40 20.60 10 5.0mm 102 5.10 84.50 15.50 11 3.35mm 64 3.20 87.70 12.30 12 2.0mm 88 4.40 92.10 7.90 13 1.18mm 35 1.75 93.85 6.15 14 600µ 42 2.10 95.15 4.85 15 300µ 33 1.65 97.60 2.40 16 150µ 18 0.90 98.50 1.50 17 75µ 22 1.10 99.6 0.40 18 Pan 8 0.40 100 In the pan we have = 100 W,= 2000 2 -99.6 = 0.4 % of material 2. 3.A sample soil is obtained and sieve analysis is performed to determined its particle distribution. Sieve Opening Mass Retained % Finer # 6 3.35 146 # 8 2.36 88 #16 1.18 125 # 40 0.425 56 #50 0.3 42 #140 0.106 127 # 200 0.075 126 Pan 29 Determine: 1. Effective Size (in mm and in 4 decimal places) 2. Uniformity Coefficient (in 2 decimal places) 3. Coefficient of Curvature (in 2 decimal places) 4. Sorting Coefficient (in 2 decimal places)
- EAM MAN TESİ MSKŪ-LMS Hydrometer and sieve analysis were conducted on a soil sample. amadı Find D10, D60, uniformity coefficient (Cu), coefficient of curvature (CC) considering the chart given below. erinden Hint: Cu=D60/D1o and CC=(D30)2 / (D10XD60) miş 100 90 80 70 60 50 40 30 20 10 SILT SAND GRAVEL 100 0,001 CLAY 0,1 10 0,01 DANE ÇAPI / PARTICLE SIZE (mm) D20: (in mm) Seς Seç. Cu 14.28 0.1 Deo: (in mm) 5.14 0.007 CC Consolidation test results are provided below, (Hint: C, or Ce = Ae/log(of/ai') ): nmadi zerinden nmiş AR 21 lenov GEÇEN DANE YÜZZDESİ / PERCENT FINER THAN DThe modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and the results are as follows: Moist Weight in Mold, gf Water Content, % 6.5 3250 9.3 3826 12.6 4293 14.9 4362 17.2 4035 18.6 3685 (a) Plot the Ya versus w relation. (b) Determine Ya.max and wopt• (c) Calculate S and e at the maximum dry unit weight point. (d) What is Y at w. (e) What is the range of water content if the relative compaction (R.C.) is required to be 95% of the modified Proctor Ya.max? pt? opr?Classify Soil C (group classification and group index) using AASHTO method. SOIL SAMPLE SIEVE NO. DIA. (mm) A В # 4 4.76 90 100 100 # 8 2.38 88 90 100 # 10 2 86 77 98 # 20 0.84 84 59 92 # 40 0.42 82 56 84 # 60 0.25 80 54 79 #100 0.15 78 51 75 #200 0.075 76 48 72 Characteristics of # 40 fraction LL 38 28 50 PL 30 45
- Find the missed data and give the result of Fineness Modulus of sample soil data given below. Weight Percentage Cumulative Percentage finer Sieve retained Weight retained percentage N = (100 - C) S.NO size retained (C) Select one: (gm) (gm) O a. 7.824 1 75mm O b. 9.438 63mm O c. 8.142 3 50mm O d. 7.649 4 37.5mm 28mm 123 6.15 6.15 6 20mm 107 5.35 11.50 7 14mm 208 10.4 21.9 8 10mm 56 2.8 24.7 6.3mm 3.9 10 5.0mm 92 4.6 33.2 11 3.35mm 308 15.4 48.6 12 2.0mm 223 11.15 59.75 13 1.18mm 188 9.4 69.15 14 600µ 282 14.1 83.25 15 300µ 96 4.8 88.05 16 150µ 88 4.4 92.45 17 75µ 103 5.15 97.6 18 pan 48 2.4 10043.) The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 100 6 2.380 98 10 2.000 91 20 0.840 85 40 0.420 84 60 0.250 79 100 0.149 61 200 0.074 55 LL 60 PL 40 ML None of the above. CL CH MHsd
- i need the answer quicklya .l zain IQ elearning7.uokufa.edu.iq CHAPTER SEVEN STERSSES WITHIN SOIL MASS Н.W The detailed results of a standard Proctor test on a soil classified as CL-ML and group name silty clay with sand are shown in the table below. Determine the maximum dry unit weight and optimum water content. Diameter of mould = 4 in. Height of mould 4.584 in. Volume of mould = 1/30 ft3. Weight of mould, M = 4.45 lb. Unit weight data Water content data Weight of wet soil and mold (Ibs) Mass of can and wet soil (grams) Mass of can and dry soil (grams) Mass of can (grams) M. M. M. 7.32 114.92 111.48 7,57 163.12 155.08 7.68 190.43 178.64 46.20 193.13 178.24 46.50 7.65 188.77 171.58 46.10 IIUrgent need please provide answer asap