SITUATION 4: The following data shows the results of the sieve analysis of two soil samples A and B. Sieve Percent Opening(mm) Passing no. B 100 A # 4 4.76 90 #8 2.38 64 98 #10 2.0 58 90 #25 #60 0.71 0.25 30 72 22 45 #100 0.149 10 25 # 200 | 0.074 11. Which of the following most nearly gives the uniformity coefficient for soil A. 4 а. 12 C. 10 12. Classify the soil A using USCS method. b. 15 d. 8 a. well graded sand b. well graded gravel C. poorly graded sand d. poorly graded gravel 13. Classify the soil B using USCS method. a. well graded sand b. well graded gravel c. poorly graded sand d. poorly graded gravel

A series of modified Proctor tests have been performed on a soil that has a Gs of 2.68. The test results obtained are as follows. Point No. Weight of Compacted Soil + Mass of Mass of Can + Moisture Content Test Results Mass of Can + Dry Mold (lb) Can (g) Moist Soil (g) 1 8.73 22.13 207.51 2 9.07 25.26 239.69 3 9.40 19.74 253.90 4 9.46 23.36 250.93 5 9.22 20.28 301.47 Soil (g) 202.30 225.27 230.64 219.74 250.95 The weight of the empty mold was 5.06 lb. Plot the laboratory test results and the S = 80% and S = 100% curves, and then draw the modified Proctor compaction curve. Determine the maximum dry unit weight (lb/ft³) and the optimum moisture content, based on the modified Proctor test. Assuming that the field compaction curve is the same as the compaction curve obtained using the modified Proctor test, determine the range of as-compacted moisture content required in the field to obtain a relative compaction of at least (a) 90%, and (b) 95%.

The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 100 No. 8 2.380 100 No. 10 2.000 95 No. 20 0.840 81 No. 40 0.420 74 No. 60 0.250 69 No. 100 0.150 55 No. 200 0.075 51 Characteristics of No. 40 Fraction LL 48 PL 40   A. A-5(3)   B. A-7-5(4)   C. None of these.   D. A-5(4)   E. A-7-6(3)

Subject: Geotechnical Engineering