The following experimental data were obtained for the kinetics of the enzymereaction Glucose + ATP → Glucose 6-phosphate + ADP.Parameters1234[S], M1.72.33.24.38.116.7V0.210.240.270.330.410.45What is the Km and Vmax of the enzyme?

Enzyme kinetics are explained by Michaelis Menten equation shown below: V=VmaxSKm+S Here, V is…

Answered: The following experimental data were…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Below is kinetic data obtained for an enzyme-catalyzed reaction. The enzyme concentration is fixed at 100 nM. Using a Lineweaver-Burke plot, calculate the kcat value for this reaction. Report your answer to three significant figures in units of 1/sec.
The following data were obtained in a study of an enzyme known to follow Michaelis-Menten kinetics: Vo (micromol/min) Substrate added (mM) 200 1.0 400 2.0 800 4.0 1600 8.0 3200 16.0 The enzyme concentration used in all reactions is 106 M. Which of the following is true: O A) The Km for the reaction must be less than 1 mM ○ B) It is possible to determine Km for the reaction, but not Vmax or kcat OC) It is possible to determine only kcat, not Vmax or Km D) It is not possible to determine Vmax for the reaction OE) The ratio Vmax/Km for the reaction cannot be determined
In an enzyme kinetics study, three inhibitors resulted to the following results: Inhibitor ABC Inhibitor XYZ Inhibitor PQR Without Inhibitor Vmax 40.2 mM/ sec 40.3 mM/ sec 12.32 mM/ sec 65.43 mM/ sec Km 24.3 mM 28.5 mM 24.3 mM 15.7 mM The inhibition occurred at 37.0°C. Assuming that the temperature increased to 37.5°C, what will happen to the Vmax and Km in the chemical system involving Inhibitor XYZ? Why do you say so? Provide illustrations using appropriate dimensions in the x and y axes. C.
You obtain a calculated Vmax of 4.26uM/s and a Km of 122.5uM from a kinetics experiment performed using 0.5uM enzyme. What is the catalytic efficiency of this enzyme?
The following data were collected in the study of a new enzyme and an inhibitor of the new enzyme: Vo (nmol/sec) [S] (µM). 1.3 - Inhibitor + Inhibitor 2.50 0.62 2.6 4.00 1.42 6.5 6.30 2.65 13.0 7.60 3.12 26.0 9.00 3.58 What is the Vmax of the inhibited enzyme reaction?
As a result of an experiment following measurements were obtained from a cell: ATP concentration of 0.5 mM, ADP concentration of 0.1 mM, inorganic phosphate (Pi) concentration of 2 mM. Under these conditions calculate the actual free energy (AG) of the reaction of hydrolysis of ATP to ADP and Pi. (The standard energy (AG°) of ATP = -31 kJ/mol; RT = 2,58 kJ/mol) Select one: O a. -28 kJ/mol O b. -33 kJ/mol OC. -19 kJ/mol O d. -42 kJ/mol
Most of the enzyme reactions followed the mathematical kinetic plots suggested by Michaelis-Menten plots: Define Vmax and KM in the equations.
The following data have been obtained for two different initial enzyme concentrations for an enzyme-catalyzed reaction. [E]=0.015 g/l) (g/l-min) [S] (g/l) v([E]=0.00875 g/l) (g/l-min) 1.14 20.0 0.67 0.87 10.0 0.51 0.70 6.7 0.41 0.59 5.0 0.34 0.50 4.0 0.29 0.44 3.3 0.39 2.9 0.35 2.5 a. Find K b. Find V for [E]=0.015 g/l. c. Find V for [E]=0.00875 g/l. d. Find k2. Use Eddie-Hostee plot to find your answer. Compare your result using Hanes- Wolf plot.

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The following experimental data were obtained for the kinetics of the enzyme reaction Glucose + ATP → Glucose 6-phosphate + ADP. Parameters 1 4 [S], M V 1.7 2.3 3.2 4.3 8.1 16.7 0.21 0.24 0.27 0.33 0.41 0.45 What is the Km and Vmax of the enzyme?