The first reaction in Glycolysis is the phosphorylation of Glucose: Pi + Glucose → Glucose 6-Phosphate + water This is a thermodynamically unfavorable process with a ∆G0’ = +13.8 kJ/mol. In a liver cell at 370C the concentrations of both phosphate and glucose are normally maintained at about 0.005 M each. What would be the equilibrium concentration of Glucose 6-Phosphate according to the above data? Note: In the biochemical standard state [H2O] = 1.0 (this will help with the question below) When the reaction described in question number 3 is coupled to the hydrolysis of ATP the equilibrium concentration of Glucose 6-Phosphate goes to: a. 10.5 b. 350 c. 3000 d. 77 e. 4.5 f. 55 g. 550 h. 652 i. 1120
The first reaction in Glycolysis is the phosphorylation of Glucose:
Pi + Glucose → Glucose 6-Phosphate + water
This is a
370C the concentrations of both phosphate and glucose are normally maintained at about 0.005 M each. What would be the equilibrium concentration of Glucose 6-Phosphate according to the above data? Note: In the biochemical standard state [H2O] = 1.0 (this will help with the question below)
When the reaction described in question number 3 is coupled to the hydrolysis of ATP the equilibrium concentration of Glucose 6-Phosphate goes to:
a. 10.5
b. 350
c. 3000
d. 77
e. 4.5
f. 55
g. 550
h. 652
i. 1120
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