The figure shows wire section 1 of diameter D1 = 5.50R and wire section 2 of diameter D2 = 4.00R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 1.70 m shown in section 2 is 13.0 µV. The number of charge carriers per unit volume is 8.70 x 1028 m-3. What is the drift speed of the conduction electrons in section 1? D (2) (1) Number Units

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The figure shows wire section 1 of diameter D1 = 5.50R and wire section 2 of diameter D2 = 4.00R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly
distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 1.70 m shown in section 2 is 13.0 µV. The number of charge carriers per unit volume is 8.70 x
1028 m-3. What is the drift speed of the conduction electrons in section 1?
D
D2
(2)
(1)
Number
Units
the tolerance is 1/ 20%
Transcribed Image Text:The figure shows wire section 1 of diameter D1 = 5.50R and wire section 2 of diameter D2 = 4.00R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 1.70 m shown in section 2 is 13.0 µV. The number of charge carriers per unit volume is 8.70 x 1028 m-3. What is the drift speed of the conduction electrons in section 1? D D2 (2) (1) Number Units the tolerance is 1/ 20%
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