The figure shows wire section 1 of diameter D₁ = 5.00R and wire section 2 of diameter D₂ = 3.50R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 2.30 m shown in section 2 is 15.0 µV. The number of charge carriers per unit volume is 8.40 x 1028 m3. What is the drift speed of the conduction electrons in section 1? Number i Units D₁ (1) (2)

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Chapter1: Units, Trigonometry. And Vectors
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The figure shows wire section 1 of diameter D₁ = 5.00R and wire section 2 of diameter D₂ = 3.50R, connected by a tapered section. The
wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the
wire's width. The electric potential change V along the length L = 2.30 m shown in section 2 is 15.0 μV. The number of charge carriers
per unit volume is 8.40 x 1028 m3. What is the drift speed of the conduction electrons in section 1?
Number
Units
(1)
Transcribed Image Text:The figure shows wire section 1 of diameter D₁ = 5.00R and wire section 2 of diameter D₂ = 3.50R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 2.30 m shown in section 2 is 15.0 μV. The number of charge carriers per unit volume is 8.40 x 1028 m3. What is the drift speed of the conduction electrons in section 1? Number Units (1)
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