The Figure shows wire section 1 of diameter D1 = 4.00R and wire section 2 of diameter D2 = 2.00R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 2.00 m shown in section 2 is 10.0 x 10-6V. The number of charge carriers per unit volume is 8.49 x 1028 m-3. What is the drift speed of the conduction electrons in section 1? D, (2) (1)

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Chapter1: Units, Trigonometry. And Vectors
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The Figure shows wire section 1 of diameter D1 = 4.00R and wire section 2 of diameter D2 = 2.00R, connected by a tapered section. The wire is copper and carries a
current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L =
2.00 m shown in section 2 is 10.0 x 10-6V. The number of charge carriers per unit volume is 8.49 x 1028 m3. What is the drift speed of the conduction electrons in
section 1?
D
D2
(2)
(1)
Transcribed Image Text:The Figure shows wire section 1 of diameter D1 = 4.00R and wire section 2 of diameter D2 = 2.00R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 2.00 m shown in section 2 is 10.0 x 10-6V. The number of charge carriers per unit volume is 8.49 x 1028 m3. What is the drift speed of the conduction electrons in section 1? D D2 (2) (1)
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