The figure below represents a graph of the electric potential in a region of space versus position x, where the electric field is parallel to the x axis. Each vertical division on the graph is equal to 20 volts. x (ст) ol 1 3 4 (a) What is the electric field at x = 0.5 cm? Positive values represent electric fields in the +x direction. |V/m (b) What is the electric field at x = 2.5 cm? V/m (c) What is the electric field at x = 3.5 cm? |V/m

The figure below represents a graph of the electric potential in a region of space versus position x, where the electric field is parallel to the x axis. Each vertical division on the graph is equal to 20 volts. x (ст) ol 1 3 4 (a) What is the electric field at x = 0.5 cm? Positive values represent electric fields in the +x direction. |V/m (b) What is the electric field at x = 2.5 cm? V/m (c) What is the electric field at x = 3.5 cm? |V/m

Similar questions

Item 15 When a nerve impulse propagates along a nerve cell, the electric field within the cell membrane changes from 7.0×105 N/C in one direction to 3.1×105 N/C in the other direction. Part A Approximating the cell membrane as a parallel-plate capacitor, find the magnitude of the change in charge density on the walls on the cell membrane. Express your answer using two significant figures. ΠΙΑΣΦΑ |Aσ| = Submit Request Answer ? C/m²
Part (a) Write an equation for the change of electric potential energy ΔU of the proton, in terms of the symbols given and the charge of the proton e. ΔU = ______ Part (b) Solve for the numerical value of the change of the electric potential energy in electron volts (eV). ΔU = ______ Part (c) How much work is done by the electric force during the motion of the proton in J? W = _______
The voltage across a membrane forming a cell wall is 80.080.0 mV and the membrane is 10.0010.00 nm thick. What is the electric field strength? You may assume a uniform electric field.
Consider a parallel-plate capacitor constructed of two square plates, 4.22 m on a side, separated by a distance 6.23 mm. If a charge of 2.85 nC is placed on one plate, with an equal but opposite charge on the other plate, find the electric field inside the capacitor. Answer in units of V/m.
What is the magnitude of the electric field at the point (2.90 i-7.20 j+5.50 k) m if the electric potential is given by V = 5.30xyz², where Vis in volts and x, y, and z are in meters? Number i Units
What is the magnitude of the work done if 3.0 C is transported between two points with a potential difference of 90 V? a. 270 J b.30 J c.90 J d.180 J
Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.30 cm. If the potential difference across the plates was 25.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates. V/m
two parallel-plate capacitors (with air between the plates) are connected to a battery. Capacitor 1 has a plate area of 2.4 cm2 and an electric field (between its plates) of magnitude 1800 V/m. Capacitor 2 has a plate area of 0.56 cm2 and an electric field of magnitude 1700 V/m. What is the total charge on the two capacitors?
What is the magnitude, in volts, of the maximum potential difference between two parallel conducting plates separated by 0.51 cm of air?
What potential difference is needed to accelerate an electron from rest to a speed of 1.2x106 m/s? Express your answer to two significant figures and include the appropriate units. μÅ AV= Value Submit Request Answer Ć Units ?
The electric field near the Earth is about 150 N/C. The radius of Earth is r = 6380 km. Approximately how much electric energy is stored in the Earth's electric field in the first 13 m above the Earth's surface? Express your answers with the appropriate units. 00 μA Uair= 5.4.10 6 Part C W Submit Previous Answers Request Answer ? X Incorrect; Try Again; 4 attempts remaining Determine the ratio of the daily output from a 2000-MW power station to the electric energy stored in the Earth's electric field in the first 13 m above the Earth's surface.
How do I rearrange this equation so that I am solving for t?