The figure below represents a graph of the electric potential in a region of space versus position x, where the electric field is parallel to the x axis. Each vertical division on the graph is equal to 20 volts. x (ст) ol 1 3 4 (a) What is the electric field at x = 0.5 cm? Positive values represent electric fields in the +x direction. |V/m (b) What is the electric field at x = 2.5 cm? V/m (c) What is the electric field at x = 3.5 cm? |V/m

icon
Related questions
Question
The figure below represents a graph of the electric potential in a region of space versus position x, where the electric field is parallel to the x axis. Each vertical division on the graph is equal to 20 volts.
x (cm)
1
3
4
(a) What is the electric field at x = 0.5 cm? Positive values represent electric fields in the +x direction.
V/m
(b) What is the electric field at x = 2.5 cm?
V/m
(c) What is the electric field at x = 3.5 cm?
V/m
Now consider the figure to represent the electric field instead of potential, with each vertical division on the graph equal to 30 N/C.
(d) What is the potential difference V,-V2, the difference in potential between x = 2 cm and x = 3 cm?
V
(e) What is the potential difference V-V,?
V
Transcribed Image Text:The figure below represents a graph of the electric potential in a region of space versus position x, where the electric field is parallel to the x axis. Each vertical division on the graph is equal to 20 volts. x (cm) 1 3 4 (a) What is the electric field at x = 0.5 cm? Positive values represent electric fields in the +x direction. V/m (b) What is the electric field at x = 2.5 cm? V/m (c) What is the electric field at x = 3.5 cm? V/m Now consider the figure to represent the electric field instead of potential, with each vertical division on the graph equal to 30 N/C. (d) What is the potential difference V,-V2, the difference in potential between x = 2 cm and x = 3 cm? V (e) What is the potential difference V-V,? V
Expert Solution
Step 1

Electric field is defined as the negative gradient of potentialFor 1d electric fields, E=-dVdxPotential V of a charge q at distance x is given asV=14πεoqxE=-ddx14πεoqxE=14πεoqx2

This electric field can also be written asE=1x14πεoqxE=1xV

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer
Similar questions
  • SEE MORE QUESTIONS