What potential difference is needed to accelerate an electron from rest to a speed of 1.2x106 m/s ? Express your answer to two significant figures and include the appropriate units. AV = HÅ Value Submit Request Answer Units ?
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When an electron enters a region of a potential difference, the electron accelerates through this potential difference, from the negative end to the positive end.
When the electron enters the potential field, it gains an electric potential energy, which as the electron accelerates and increases its speed, is converted into its kinetic energy.
The potential energy of an electron in a potential field of voltage V is given as
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- The voltage across a capacitor is given by the formula V=Q/C, where Q is usually called "the charge on the capacitor." Where is this charge in a capacitor? Does the capacitor really have a net charge?An electron is fired at a speed vi = 4.3 × 106 m/s and at an angle θi = 39.7° between two parallel conducting plates as shown in the figure. If s = 1.7 mm and the voltage difference between the plates is ΔV = 99.8 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor. Round your answer to 6 decimal places.Please solve asap in detail
- Calculate the potential at point P as shown in the diagram. a. 1.4 x 10^4 V b. 1.4 x 10^6 V c. 2.1 x 10^4 V d. 1.7 x 10^6 VSpeed of an Electron between Two Charges Two stationary positive point charges, charge 1 of magnitude 3.60 nC and charge 2 of magnitude 1.60 nC, are separated by a distance of 41.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. Part A What is the speed Ufinal of the electron when it is 10.0 cm from charge 1? Express your answer in meters per second. ▸ View Available Hint(s) Ufinal = Submit Provide Feedback ΜΕ ΑΣΦ 跖 ? m/s Review ICSuppose in the figure(Figure 1) that C1=C2=C3=40.9μFC1=C2=C3=40.9μF and C4=71.2μFC4=71.2μF. a.If the charge on C2C2 is Q2=20.7μCQ2=20.7μC, determine the charge on each of the other capacitors. Enter your answers numerically separated by commas. Determine the voltage across each capacitor. Enter your answers numerically separated by commas. Determine the voltage Vabacross the entire combination.
- Two 2.10 cm x 2.10 cm plates that form a parallel- plate capacitor are charged to ±0.708 nC. ▾ Part A What is the electric field strength inside the capacitor if the spacing between the plates is 1.30 mm? Express your answer with the appropriate units. E= Value Submit Request Answer Part B ? Units What is potential difference across the capacitor if the spacing between the plates is 1.30 mm ? Express your answer with the appropriate units. HÅ V = Value Units Submit Request Answer Part C ? What is the electric field strength inside the capacitor if the spacing between the plates is 2.60 mm ? Express your answer with the appropriate units. με E = Value Units Submit Request Answer Part D ? What is the potential difference across the capacitor if the spacing between the plates is 2.60 mm ? Express your answer with the appropriate units. ΜΑ ? V = Value Units Submit Request Answer Provide FeedbackAn electron is fired at a speed vi = 3.1 × 106 m/s and at an angle θi = 36.8° between two parallel conducting plates as shown in the figure. If s = 1.8 mm and the voltage difference between the plates is ΔV = 98.8 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor30 25 y = 0.8x + 1.2 %3D 20 15 10 15 20 25 30 For the plot and trendline equation above, the x-data is electric potential in volts (V) and the y-data is power in watts (W). What is the value of m? What is the value of b? w] 10
- The electric potential difference AV, also called voltage, is expressed in terms of the electric field as follows AV = Edr where, a is the initial position and b is the final position. If an electric field in a region in space is defined as E= - 2Br? where B is just a constant without an arbitrary value. What is the electric potential difference from position 0 to R?1. You have five 10.0 F capacitors. Show all the possible connections for the five capacitors to produce a total capacitance of 50.0 F. 2. Suppose the space between the plates of the capacitor in Sample Problem 2.6 item number 2 is filled with equal thicknesses of the same dielectrics but arranged as shown. What is its capacitance? 3. The capacitors in Sample Problem 2.6 item number 3 are connected in parallel instead of being in series. The combination is connected to a 100 V line. Find the (a) total capacitance, (b) charge stored in each capacitor, and (c) potential difference across each capacitor.Two 2.50 cm x 2.50 cm square aluminum electrodes are spaced 0.530 mm apart. The electrodes are connected to a 140 V battery. Part A What is the capacitance? Give your answer in picofarads. (pico = 10-12) ? C = 1.044 pF Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B What is the charge on each electrode? Give your answer in nanocoulombs. Ηνα ΑΣφ x•10" Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining