Rutherford's Planetary Model of the Atom In 1911, Ernest Rutherford developed a planetary model of the atom, in which a small positively charged nucleus is orbited by electrons. The model was motivated by an experiment carried out by Rutherford and his graduate students, Geiger and Marsden. In this experiment, they fired alpha particles with an initial speed of 1.30 x 10 m/s at a thin sheet of gold. (Alpha particles are obtained from certain radioactive decays. They have a charge of +2e and a mass of 6.64 x 10-27 kg.) ▾ Part A How close can the alpha particles get to a gold nucleus (charge= +79e), assuming the nucleus remains stationary? (This calculation sets an upper limit on the size of the gold nucleus. See Chapter 31 of the textbook for further details.) EVE| ΑΣΦ ↑ 4.8. 10-14 Submit Previous Answers Request Answer 2 m

Rutherford's Planetary Model of the Atom In 1911, Ernest Rutherford developed a planetary model of the atom, in which a small positively charged nucleus is orbited by electrons. The model was motivated by an experiment carried out by Rutherford and his graduate students, Geiger and Marsden. In this experiment, they fired alpha particles with an initial speed of 1.30 x 10 m/s at a thin sheet of gold. (Alpha particles are obtained from certain radioactive decays. They have a charge of +2e and a mass of 6.64 x 10-27 kg.) ▾ Part A How close can the alpha particles get to a gold nucleus (charge= +79e), assuming the nucleus remains stationary? (This calculation sets an upper limit on the size of the gold nucleus. See Chapter 31 of the textbook for further details.) EVE| ΑΣΦ ↑ 4.8. 10-14 Submit Previous Answers Request Answer 2 m

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Two negative charges are at rest. Each has a charge of -0.03 C and a mass of 3.4 x 10-6 kg. a. If they are 4 meters apart, what are their potential, kinetic, and mechanical energies? (All three energies will be the same for both charges.) b. Now one of the charges has moved to a point 0.3 meters farther away from the other. What are this charge’s kinetic, potential, and mechanical energies? What is its speed? c. This same charge has now moved to a point 1.2 meters farther away from the other. What are its kinetic, potential, and mechanical energies now? What is its speed?
An alpha particle (with a charge of +2 e and a mass of 6.64 x 1027 kg) is fired at a fixed gold nucleus (with a charge of +79 e ) from very far away. The alpha particle makes it a point a distance of 2.0 x 106 m away from the gold nucleus before flying backwards away. A. Determine the potential energy of the alpha particle and gold nucleus pair when they are 2.0 x 10-6 m apart. B. What is the kinetic energy of the alpha particle when it reaches this turning point? How do you know? C. What is the potential energy of the alpha particle and gold nucleus pair when they are very far apart? How do you know? D. Determine the initial speed of the alpha particle (when it was very far away from the gold nucleus).
Have you ever chewed on a wintergreen mint in front of a mirror in the dark? If you have, you may have noticed some sparks of light coming out of your mouth as you chewed on the candy; and, without knowing it, you have experienced a physical phenomenon called triboluminescence. In this problem you will analyze some of the key elements of triboluminescence in wintergreen candies. When you break a sugar crystal with your teeth, energetic electrons, released by the broken chemical bonds, collide with nitrogen molecules in the air. As a result of these collisions, the electrons in the nitrogen molecules jump to a state of higher energy; when they decay to their ground state, radiation is emitted. ▼ Part A Imagine that an electron in an excited state in a nitrogen molecule decays to its ground state, emitting a photon with a frequency of 8.88×1014 Hz. What is the change in energy, AE, that the electron undergoes to decay to its ground state? Express your answer in electron volts to three…
An alpha particle (charge +3.20 x 10-19C, mass 6.64 x 10-27kg) is initially 5.2 cm away from a fixed gold nucleus (charge +1.26 x 10-17C, mass 3.29 x 10-25kg) and moving toward the nucleus with a speed of 8.1 x 105m/s. How close to the nucleus does the alpha particle get? (Note: The nucleus diameter is approximately 10-14m and the and alpha particle’s is 10-15m.)
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-- / • ,\ Question 5 Conductors are materials in which All electrons are bound to atoms and cannot 1 move freely through the material. All Neutron are bound to atoms and cannot 2 move freely through the material. All electrons are bound to atoms and can 3 move freely through the material. All Neutron are bound to atoms and 4 canmove freely through the material.
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QUESTION 9 Which of the following statements is not true for a solid conductor in electrostatic equilibrium? a. The electric potential inside the conducting material must be zero. b. The electric field is perpendicular to the outer surface of the conductor. C. The excess charge resides solely on the outer surface of the conductor. d. The outer surface of the conductor is an equipotential surface. e. The electric field is zero everywhere inside the conducting material.
2 Rutherford +2e +79e Rutherford discovered the nucleus of atoms by firing a particles at gold foil. An a particle has a charge of q = +2e and a mass of m = 6.64 x 10-27 kg. A gold nucleus has charge of Q = +79e. You may ignore the motion of the gold nucleus in this problem. Suppose an a particles is traveling directly toward a gold nucleus. If the speed of the a particle is v = 1.9 x 10' m/s when it is 1.0 m from the gold nucleus, how close to the gold nucleus will the a particle come before it stops and reverses direction?
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An electron accelerates between the cathode and the anode. It passes through a potential difference of 2000 v. The charge on an electron is 1.6 × 10-19 C and the mass of an electron is 9.1 x 10-31 kg. Find the following: A. Describe what is happening to the atoms in the screen as they are hit by electrons. B. State the kinetic energy, in ev, of the electron when it hits the screen. C. Calculate the work done on the electron passing through a pd of 2000 V. Give your answer in joules. D. The work done on the electron becomes kinetic energy of the electron. Write down the formula for kinetic energy in terms of mass m and speed v. E. Using your answers to questions 3 and 4, find the speed of the electron. F. The anode is connected to the screen. State and explain what, if anything, happens to the speed of the electron as it passes from the anode to the screen. G. In 10 seconds, 6.0 × 10^17 electrons hit the screen. Calculate: (a) the charge hitting the screen in 10 seconds (the charge on…
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