**Section A:**From Equation 25.6, we have the following:\[\Delta V = -Ed = (-7.2 \times 10^4 \, \text{V/m})(0.60 \, \text{m}) = \_\_\_\_\_\_\_\_ \, \text{V}\]**Section B:**From Equation 25.3, we have the following:\[\Delta U = q \Delta V = e \Delta V = (1.6 \times 10^{-19} \, \text{C})(\Delta V) = \_\_\_\_\_\_\_\_ \, \text{J}\]The negative sign indicates a decrease in potential energy as the proton moves in the direction of the electric field. This change is consistent with energy conservation in an isolated system: when a proton accelerates along the direction of the electric field, it gains kinetic energy while losing electric potential energy. This principle is utilized in devices like electron guns for TV picture tubes and particle accelerators for research in particle physics.You can predict and observe the speed of a proton as it arrives at the negative plate for random electric field values using this [Interactive Example](#).---**Exercise 25.2:***Hints: Getting Started | I'm Stuck*For the previous example, apply the principle of energy conservation to find the speed of the proton after it has moved 0.60 m, starting from rest.\_\_\_\_\_\_\_\_ m/s

Electric field (E) = 7.2×104 Vm Distance moved (d) = 0.60 m

LA From Equation 25.6, we have the following. AV = -Ed = -(7.2 × 104 v/m)(0.60 m) = B] V From Equation 25.3, we have the following. AU = qAV = eAV = (1.6 x 10-19 C)(AV) = The negative sign means that the potential energy of the system decreases as the proton moves in the direction of the electric field. This decrease is consistent with the conservation of energy in an isolated system: as the proton accelerates in the direction of the field, it gains kinetic energy and at the same time the system loses electric potential energy. The increase in kinetic energy of a charged particle in an electric field is exploited in many devices, including electron guns for TV picture tubes and particle accelerators for research in particle physics. You can predict and observe the speed of the proton as it arrives at the negative plate for random values of the electric field using this Interactive Example. Exercise 25.2 Hints: Getting Started | I'm Stuck For the previous example, apply the principle of energy conservation to find the speed of the proton after it has moved 0.60 m, starting from rest. m/s

LA From Equation 25.6, we have the following. AV = -Ed = -(7.2 × 104 v/m)(0.60 m) = B] V From Equation 25.3, we have the following. AU = qAV = eAV = (1.6 x 10-19 C)(AV) = The negative sign means that the potential energy of the system decreases as the proton moves in the direction of the electric field. This decrease is consistent with the conservation of energy in an isolated system: as the proton accelerates in the direction of the field, it gains kinetic energy and at the same time the system loses electric potential energy. The increase in kinetic energy of a charged particle in an electric field is exploited in many devices, including electron guns for TV picture tubes and particle accelerators for research in particle physics. You can predict and observe the speed of the proton as it arrives at the negative plate for random values of the electric field using this Interactive Example. Exercise 25.2 Hints: Getting Started | I'm Stuck For the previous example, apply the principle of energy conservation to find the speed of the proton after it has moved 0.60 m, starting from rest. m/s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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