An electron is to be accelerated in a uniform electric field having a strength of 2.2.106 V m (a) What energy in keV is given to the electron if it is accelerated through 0.4 m? AKE = keV (b) Over what distance (in km) would it have to be accelerated to increase its energy by 55 GeV? d = km Hint: How is potential energy, PE, gained by an electron related to the uniform electric field? How is the potential difference, V, related to the uniform electric field?

An electron is to be accelerated in a uniform electric field having a strength of 2.2.106 V m (a) What energy in keV is given to the electron if it is accelerated through 0.4 m? AKE = keV (b) Over what distance (in km) would it have to be accelerated to increase its energy by 55 GeV? d = km Hint: How is potential energy, PE, gained by an electron related to the uniform electric field? How is the potential difference, V, related to the uniform electric field?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Two 2.2-cm-diameter-disks spaced 1.7 mm apart form a parallel-plate capacitor. The electric field…

Q: An electron is accelerating under a potential difference of 105 volts. (m,=9,108x1031) a) What is…

A: The potential energy of the electron gets converted into the kinetic energy. Thus, the kinetic…

Q: Two protons, initially separated by a very large distance (ri is infinity), move directly toward…

A: charge on each proton (q) = 1.6×10-19 C distance of closest approach (d) = 8×10-14 m

Q: Particle A has a charge of –10µC and a mass of 0.001kg. Particle A starts in a position where the…

A: Given Data Charge of particle A is qA=-10 μC=-10×10-6 C Mass of the particle is m=0.001 kg Potential…

Q: A small metallic sphere has a mass of 8.00x10^-6 kg and a charge of -2.5 uc (microcoulombs). If the…

Q: 3. An electron enters a parallel plate apparatus 10.0 cm long and 2.0 cm wide, moving horizontally…

Q: Two 2.0-cm-diameter disks spaced 1.5 mm apart form a parallel-plate capacitor. The electric field…

A: Givendiameter, d=2 cmradius, r=1 cmseparation , t=1.5 mmE=5×105 V/mcapacitance, C=Aεotwhere A is…

Q: V An electron is to be accelerated in a uniform electric field having a strength of 2.1 10° 1. (a)…

Q: A doubly charged ion is accelerated to an energy of 37.0 keV by the electric field between two…

A: Energy, E = 37.0 keV = 37×10³×1.6×10-19 J = 5.92×10-15 JSeparation, d = 1.50 cm = 0.015 m

Q: A double charged ion is accelerated to an energy of 30.9 keV by the electric field between two…

A: Energy of double charged ion is Separation between parallel conducting plates is Note:Find:Magnitude…

Q: If a Cu2+ ion that is initially at rest accelerates through a potential difference of 12 V without…

Q: Review Multiple-Concept Example 4 to see the concepts that are pertinent here. In a television…

A: potential difference = 22000 V

Q: An Electron is emitted by heating a cathode and is accelerated by the potential difference of V…

A: Given information: Here, ΔV is the difference in potential between the upper and the lower plates,…

Q: In large CRT televisions, electrons are accelerated from rest by a potential difference of 23.88 kV…

Q: The distance, r, between the proton and electron in the hydrogen atom is about 10-10 m. Determine…

Q: 9. An electron starts from rest 32.5 cm from a fixed point charge with Q=-0.125µC. How fast will the…

Q: Which of the following is/are true? Statement A: A proton moving through a potential difference of…

A: Required : The correct option.

Q: The electrons in a CRT are accelerated through a potential difference of 30kV. Do the electrons move…

A: Given The potential difference is ∆V=30 kV=30×103 V. If the potential difference is positive then…

Q: An electron is to be accelerated in a uniform electric field having a strength of 2x106 V/m.…

Q: An electron is accelerated from rest through a potential difference of 1.2 kV. Find the change in…

Q: A particle with a mass of 1.50x10^-5kg and a negative charge of -9.00x10^-6C is constrained to move…

A: Mass of particle = 1.5*10^-5kg Negative charge (q) = -9*10^-6C V(x) = 3x^4 volt

Q: An electron is accelerated from rest through a potential difference of 181 V. What is the electron's…

Q: A proton is fired with a speed of vi=178260.0m/s from the midpoint of the capacitor shown towards…

A: Given that: Initial speed: vi=178260.0 m/scharge of proton: q=+1.6×10-19 C (known)mass of proton,…

Q: Two 2.2-cm-diameter-disks spaced 1.7 mm apart form a parallel-plate capacitor. The electric field…

Q: If an electron is accelerated from rest through a potential difference of 1200 V, find its…

Q: An electron is to be accelerated in a uniform electric field having a strength of 2x10^6 V/m.…

A: Given data:Uniform electric field, E=2×106 V/mDistance, d=0.4 m

Q: A charged particle that has a mass of 2.8 x 10 1 kg accelerates upward at 3.6 m/s in the electric…

A: Given that a charged particle moves through plates which are held at some potential, m=2.8×1016…

Q: volts done by the electric force on a proton that

Q: Problem 3: Consider two points in an electric field. The potential at point 1, V₁, is 28 V. The…

A: Potential at point 1 is Potential at point 2 is A proton is moved from point 1 to point…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

100%

An electron is to be accelerated in a uniform electric field having a strength of 2.2.106
(a) What energy in keV is given to the electron if it is accelerated through 0.4 m?
AKE =
keV
V
(b) Over what distance (in km) would it have to be accelerated to increase its energy by 55 GeV?
d =
km
Hint: How is potential energy, PE, gained by an electron related to the uniform electric field? How is
the potential difference, V, related to the uniform electric field?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1: Given :-

VIEW

Step 2: Calculation of energy and distance :-

VIEW

Solution

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

11. An electron in the picture tube of an old television set is accelerated from rest through a potential difference Vba = +5000V. a. What is the change in potential energy of the electron? (ans: -8.0 x 1010 J) b. What is the speed of the electron as a result of this acceleration? (ans: 4.2 x 10' m/s) c. What is the speed of a proton that is accelerated through a potential difference Vba = - 5000 V? (ans: 9.8 x 10° m/s) 020-12-11 Page 4 of 17
3a. What is the potential energy U of this lightning bolt? U = 310 Joules of the square? Find 30 (1.0x10) 3b. If all this energy where to be converted to kinetic energy, what would be the speed of a m = 1000 kg car. Vf = r16 = 34 = m/s 16. These charges are numbered as: raw the re Redraw the rectangle with the actual charges (evaluate 2q1, 492, etc.) 16a. What is the distance between the indicated pairs of charges. Find these in meters. r24 = r26 = 15 = 35 = 1 2 3 MI 4 5 6 ainT 16b. Starting with all the charges at ∞, what is the potential at the upper left corner, and how much work is done to put the charge at the upper left corner? V₁ = 05 P278 Volts W₁ = Joules V3 = V13 + V23 = | srpC = 10-12 C on m 16c. What is the potential at the location of 2, due to the previous charges? How much work is done to bring in the 2nd charge? Make sure you use the correct distance. V₂ = V12 = Volts W₂ = 16d. What is the potential at the location of 3, due to the previous charges? How much work is…
An electron (m = 9.1 x 10-31 kg, q = -1.6 x 10-1⁹ C) in the picture tube of a TV is accelerated from rest through a potential difference of AV = 5000 V. What is the final speed of the electron? CQ1: Which of the following is true? A) The electron accelerates from a region of lower potential to a region of higher potential (V, > V₁). B) The electron accelerates from a region of higher potential to a region of lower potential (Vƒ < Vj). C) There's not enough information to determine whether A or B is true.
The difference in electric potential between the accelerating plates in the electron gun of a TV tube is 25 kV, while the distance between them is 1.5 cm. The magnitude of the uniform electric field between the plates is 3.8 10 2 v/m. 5.6 10² v/m. O 1.7 106v/m. 11'108 v/m.
A doubly charged ion is accelerated from rest to a kinetic energy of 31.5 keV by the electric field between two parallel conducting plates separated by 1.75 cm. What is the electric field strength between the plates, in volts per meter?
What is the speed of an electron after being accelerated from rest through a 2.5×107 V potential difference? Express your answer as a fraction of cc.
QUESTION 4 An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate. The plates are separated by a distance of 1.39 cm, and the electric field within the capacitor has a magnitude of 1743307 V/m. What is the kinetic energy of the electron just as it reaches the positive plate? (Give your answer in 2 d.p. with scientific notation(i.e. 1.23e-12)} 1 Electric field Electron F + + + + + + + + + +
An electron is to be accelerated in a uniform electric field having a strength of 1.90 106 V/m. (a) What energy in keV is given to the electron if it is accelerated through 0.810 m?_________ keV(b) Over what distance would it have to be accelerated to increase its energy by 50.0 GeV (as in the Stanford Linear Accelerator, which is actually smaller than this)? ________km
Problem 4 (practice): A mad scientist considers creating a roller coaster which would use a uniform electric field to accelerate the roller coaster cars at the start of the ride. One coaster car has a mass of 250 kg, and the scientist manages to place 0.003 C of charge on it. How strong of an electric field would they need in order to get the coaster to go from rest to a speed of 17 m/s within a distance of 20 meters?
A cathode-ray tube accelerates electrons to a speed of 26500 kms−1V. What is the potential difference across the tube?
1. An electron is to be accelerated in a uniform electric field having a strength of 2.1-106 (a) What energy in keV is given to the electron if it is accelerated through 0.3 m? AKE = keV m (b) Over what distance (in km) would it have to be accelerated to increase its energy by 43 GeV? d = km Hint: How is potential energy, PE, gained by an electron related to the uniform electric field? How is the potential difference, V, related to the uniform electric field?
.A certain parallel-plate capacitor is filled with a dielectric for which k = 4.58. The area of each plate is 0.0726 m², and the plates are separated by 1.13 mm. The capacitor will fail (short out and burn up) if the electric field between the plates exceeds 217 kN/C. What is the maximum energy that can be stored in the capacitor?