When a nerve impulse propagates along a nerve cell, the electric field within the cell membrane changes from 7.0x105 N/C in one direction to 3.1×105 N/C in the other direction. ▾ Part A Approximating the cell membrane as a parallel-plate capacitor, find the magnitude of the change in charge density on the walls on the cell membrane. Express your answer using two significant figures. ΙΨΕΙ ΑΣΦ 6 |Ag] = Submit Request Answer ? C/m²

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Item 15
When a nerve impulse propagates along a nerve cell, the electric field within
the cell membrane changes from 7.0×105 N/C in one direction to 3.1×105
N/C in the other direction.
Part A
Approximating the cell membrane as a parallel-plate capacitor, find the magnitude of the change in charge density on the walls on the cell membrane.
Express your answer using two significant figures.
ΠΙΑΣΦΑ
|Aσ| =
Submit
Request Answer
?
C/m²
Transcribed Image Text:Item 15 When a nerve impulse propagates along a nerve cell, the electric field within the cell membrane changes from 7.0×105 N/C in one direction to 3.1×105 N/C in the other direction. Part A Approximating the cell membrane as a parallel-plate capacitor, find the magnitude of the change in charge density on the walls on the cell membrane. Express your answer using two significant figures. ΠΙΑΣΦΑ |Aσ| = Submit Request Answer ? C/m²
Expert Solution
Step 1

Given, 

Electric Field in one direction = 7×10N/C

Electric Field in another direction = 3.1× 105 N/C

We need to calculate, 

Magnitude of charge in charge density =? 

 

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