An alpha particle with a kinetic energy of 7.00 MeV makes head-on collision with a gold nucleus at rest. ▼ Part A What is the distance of closest approach of the two particles? (Assume that the gold nucleus remains stationary and that it may be treated as a point charge. The atomic number of gold is 79, and an alpha particle is a helium nucleus consisting of two protons and two neutrons.) Express your answer in meters. d= Submit 5. ΑΣΦ Request Answer m
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The charges on the alpha particle and gold particles are goven as:
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- Number 1 part a b and c 1. The element gold, 797 Au, has a density of 19300kg/m?. (a) How many electrons are there in 15g of gold? (Assume that it is no net charge). (b) If this 15g is given a net charge of 25uC, approximately how many electrons were removed? (c) Approximately what fraction of the total number of electrons were removed?Please fill in the blanks. A non-uniformly charged insulating sphere has a volume charge density rho that is expressed as rho equals beta r where beta is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for beta?A system of 1358 particles, each of which is either an electron or a proton, has a net charge of -1.002x10-16 C. How many electrons are in this system (exactly)? Submit Answer Tries 0/32 What is the mass of this system (to three significant digits)?
- In the Figure below a distribution of four point charges is given. It is also given that q1 d = 5 µm (1µm = 10-6 m). The constant e is equal to the fundamental charge in nature e = 1.6×10-19 C. Find the Ex 92 = 5e, q3 = 3e, q4 = -12e and the distance %3D [ Select ] * and Ey [Select ] components of the net Electric Field at the origin in N/C units. y 94 91=92=5e 93=3e 94=-12e d-5μm 93 d 92 dSolar wind is a flow of heavily charged ions emanating from the Sun’s corona. Spectroscopic analysis suggests it contains a density of approximately 5.0 electrons per cubic centimeter (cm3). Given that the elementary charge ? ≈ 1.6 × 10−19 ? and using the combined average of your measured values of Q, determine the charge density of a cubic meter (m3) of solar wind sample as a function of QSuppose we have a charge, q1=1 μC. This charge makes an electric field some distance r=60 cm away from it. Now suppose our measurement of q1 is only accurate to within 0.1 μC, and our measurement of r is only accurate to within 2 cm. What is the uncertainty in our field calculation due only to the uncertainty in the charge separation r? for the uncertainty of q I got 2500 N/C. I keep getting 1667.67 N/C for the uncertainty for the separation of r but that is wrong
- There are two beads which are iolentread has and charge, mass, m 9. what is the condítion for them to stay in cquidibrium ? Find the charge in terms of m. 3, d, k, R , d. R © is it possible d=2R ? why?During operation, a device sprays droplets of aqueous liquid of average diameter 100 µm and charge density p = 30 mC.kg¬1. 1. Express the mass of a droplet as a function of its diameter d and the mass density My of the liquid. 2. Assuming that the mass density of a hydroalcoholic solution is the same as that of water, calculate the mass of a droplet of sprayed liquid. 3. Express the charge Q of a droplet as a function of the charge density per unit mass p and the mass of that droplet. Deduce the average charge carried by a droplet using p= 30 mC.kg¬1. 4. Has the droplet lost or gained electrons ? How many electrons does this charge represent ? (CtrlUse the following constants if necessary. Coulomb constant, k of the Charge of one electron, e= symbol carries their usual meaning. For example, µC means micro coulomb. 8.987 x 10° N - m? /C?. Vacuum permitivity, en = 8.854 x 10-12 F/m. Magnitude 9.10938356 x 10 31 kg. Unless specified otherwise, each 1.60217662 x 10 19 C. Mass of one electron, m. Suppose you have 5 point charges q to qs distributed along a semi-circle maintaining equal distance. The charge gs is at the center of the circle. The radius of the semi-circle is R = 28 cm and the magnitude of the charges are as follows : q1 24 uC, 92 29 µC and g 27 µC. c) Find the vector that points from q3 to q6 and call it 3,6. I component of the vector Give your answer to at least three significance digits. III y component of the vector Give your answer to at least three significance digits. d) Calculate the coulomb force on g6 due to q3 in unit vector notation and call it F3,6. I component of the force Give your answer to at least three…
- Atoms have an equal number of electrons and protons so are electrically neutral. Atoms that have a net electrical charge are known as "ions". Positive ions - have "missing" electrons Negative ions - have "excess" electrons 3. The net charge of an object can be found be summing the individual charges. Since charge is quantized, all net charges are just an integer multiple of the elementary charge. q-ne where q is the net charge and n is an integer. For example, sodium can be a +1 ion and chlorine can be a -1 ion. What does this mean concerning their charge and structure? Revised 1/20 L2 D Ctlo But, what if you want to look at larger objects that are charged; e.g., objects made up of a huge number of atoms/molecules. How do these objects become charged?The three charge configurations are shown in the figure. For the values of q1=3.5uC, q2=-3.5 MC and q3=5 uC. The Forces of the three charges is calculated at q3. (Note:u=micro= 10^-6, If q3 has the mass of 10 grams, what will be the initial acceleration of q3 in m/s^2, due to q1 and q2?Problem 12: The classic Millikan oil drop experiment was the first to obtain an accurate measurement of the charge on an electron. In it, oil drops were suspended against the gravitational force by a vertical electric field. microscope ©theexpertta.com Given that the oil drop is 0.85 µum in radius and has a density of 925 kg/m³, find the weight of the drop in N. W = sin() cos() tan() 7 8 9 HOME cotan() asin() acos() sinh() 4 5 6 atan() acotan() 1 2 3 cosh() tanh() cotanh() + - END ODegrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! If the drop has a single excess electron, find the electric field strength needed to balance its weight.