The protons in a nucleus are approximately 2 x 10-15 m apart. Consider the case where the protons are a distance d = 1.87 x 10-15 m apart. Calculate the magnitude of the electric force (in N) between two protons at this distance.
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- choose the letter of the correct answer.Considering electron and proton as two charged particles separated by d = 4.5 x 10m calculate the gravitational force between the proton and electron and find its ratio to the Coulomb force. Take the mass of the proton 1.7 x 10-27 kg, the mass of the electron 9.1 x 10-³1 kg, the value of 1 the universal gravitational constant 6.7 × 10-¹1 N kg-2m-2, the electron charge -1.6 × 10- C and = 9 x 10⁹ m/F. Give the answer for Απερ the gravitational force in 10-47 N. 19One form of nuclear radiation, beta decay, occurs when a neutron changes into a proton, an electron and a neutral particle called a neutrino. When this change happens to a neutron within the nucleus of an atom, the proton remains behind in the nucleus while the electron and neutrino are ejected from the nucleus. The ejected electron is called a beta particle. One nucleus that exhibits beta decay is the isotope of hydrogen 3H, called tritium, whose nucleus consists of one proton (making it hydrogen) and two neutrons (giving tritium an atomic mass m = 3u). Tritium is radioactive, and it decays to helium. Suppose an electron is ejected from a 3H atom, which has a radius of 1.000×10-14 m. The resulting 3He atom has the same radius as the 3H atom. What is the escape velocity of the electron ejected from the process? Note: Your answer may be larger than the speed of light which is okay in this scenario. To solve this problem correctly we would need to use special relativity.
- only 7 and 8An alpha particle (charge 2e) is aimed directly at a gold nucleus(charge 79e). What minimum initial kinetic energy must the alphaparticle have to approach within 7.0 * 10-14 m of the center of thegold nucleus before reversing direction? Assume that the gold nucleus,which has about 40 times the mass of an alpha particle, remains at rest.How much work is required to set up the four-charge configuration of the figure if q = 3.59 pC, a = 74.0 cm, and the particles are initially infinitely far apart and at rest? +1 -9 +q
- Say you have a point charge of one Coulomb and a hydrogen atom some distance away. Within what distance would the difference of forces on the proton and electron from the Coulomb charge exceed the attraction between the proton and electron that holds the hydrogen atom together. Treat the hydrogen atom as a proton and electron 0.53 × 10−10 m (a.k.a., one Bohr radius) apart.The three charge configurations are shown in the figure. For the values of q1=3.5uC, q2=-3.5 MC and q3=5 uC. The Forces of the three charges is calculated at q3. (Note:u=micro= 10^-6, If q3 has the mass of 10 grams, what will be the initial acceleration of q3 in m/s^2, due to q1 and q2?A hydrogen atom when in its lowest energy state consists of a proton nucleus of charge +e (remember that +e = 1.6 x 10-19 C) and an electron of charge -e and mass of 9.1 x 10-31 kg. In the Bohr model of the atom, the electron moves around the nucleus in an approximately circular orbit with a radius of 0.52 x 10-10 m. The speed of the electron when in this lowest energy orbit is approximately 2.3 x 106 m/s. Imagine that we want to ionize this atom (that is free up the electron from its nucleus) by launching ANOTHER electron at the atom to break it apart. If we were to launch this electron from very far away from the atom, then how fast must it be launched in order to break apart the atom, so that all three particles (the proton and two electrons) end up at rest, very far apart?