Use the following constants to calculate the problem:  me=9.1*10-31 kg mp=1.67*10-27 kg e=1.6*10-19 C k=8.99*109 Nm2/C2 r=1.11*10-10 m   ?=6.67⋅10−11??2??2G=6.67⋅10−11Nm2kg2 Please give your answer FE/FG in FE/FG*1040

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Chapter1: Units, Trigonometry. And Vectors
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In a hydrogen atom an electron is orbiting a proton. There are two forces between the electron and the proton. The Gravitational Force FG and the electrostatic Force FE.  What is the factor  

F/ FG 

 of those two forces. 

 

Use the following constants to calculate the problem: 

me=9.1*10-31 kg

mp=1.67*10-27 kg

e=1.6*10-19 C

k=8.99*109 Nm2/C2

r=1.11*10-10 m

 

?=6.67⋅10−11??2??2G=6.67⋅10−11Nm2kg2

Please give your answer FE/FG in FE/FG*1040

ie. for 6.734*1042  please write  673.4

 

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