**Question 1:**Particle 1 with charge \(+4e\) is located at a distance \(d_1 = 3.00 \, \text{mm}\) from the x-axis. Particle 2 with charge \(+6e\) is at the origin of the coordinate system. Particle 3 with charge \(-3e\) lies on the x-axis. The distance between particle 1 and particle 3 is \(d_2 = 5.00 \, \text{mm}\). **Problem Statement:**What is the x-component of the Coulomb force on particle 1 due to particle 2 and particle 3? The charge \(e = 1.60 \times 10^{-19} \, \text{C}\).**Diagram Explanation:**The diagram illustrates the arrangement of three charged particles:- Particle 1 is located on the x-axis at a horizontal distance, and it has a perpendicular vertical line showing its distance \(d_1\) from the x-axis. - Particle 2 is at the origin \((0, 0)\) on the x-y coordinate plane. - Particle 3 lies on the y-axis above particle 2 and is a distance \(d_1\) above it. Particle 3 is connected by a line to particle 1, with the line making an angle \(\theta\) with the horizontal x-axis. The distance between particles 1 and 3 is denoted as \(d_2\). This arrangement forms a right triangle where:- The base along the x-axis is the distance \(d_2\) between particles 1 and 3.- The height (\(d_1\)) is the vertical distance from the x-axis to particle 3.

Note: In the diagram, the position of particle 1 and 3 are interchanged as in the question it is…

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