College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:Consider a parallel plate capacitor whose plates have a charge density n. An anti-proton (a particle with the same mass as a proton, but opposite charge) starting at the positive
plate is shot at a velocity of vo= 30, 000 m/s towards the negative plate.
1. What is the minimum electric field strength needed between the plates if the proton is not to hit the top plate?
2. Describe the anti-proton's trajectory.
12°
Vo
45°
2.0 cm
++++
Expert Solution

Step 1: Minimum electric field strength
Minimum electric field strength
To calculate the minimum electric field strength needed between the plates, we can use the following equation:
F_e = qE
where:
- F_e is the electric force on the anti-proton
- q is the charge of the anti-proton
- E is the electric field strength
Since the anti-proton has a negative charge, the electric force will be in the opposite direction of the electric field. Therefore, in order to prevent the anti-proton from hitting the top plate, the electric force must be equal to the weight of the anti-proton.
F_e = mg
where:
- m is the mass of the anti-proton
- g is the acceleration due to gravity
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