E = E1E = 0E= E1E= E1The electric field is measured all over a cubical surface, and the pattern of field detected is shown in the figure above. On the right sideof the cube, the electric field has magnitude Ej = 426 V/m, and the angle between the electric field and the surface of the cube is0 = 15 degrees. On the bottom of the cube, the electric field has the same magnitude Ej, and the angle between the electric field andthe surface of the cube is also 0 = 15 degrees. On the top of the cube and the left side of the cube, the electric field is zero. On half ofthe front and back faces, the electric field has magnitude Ej and is parallel to the face; on the other half of the front and back faces, theelectric field is zero. One edge of the cube is 41 cm long.Part 1What is the net electric flux on this cubical surface?Net electric flux =iV•mSave for LaterAttempts: 0 of 4 usedSubmit Answer

Given:Electric field(EF) magnitude, E1 = 426 V/mangle made θ1 = 15olength of the edge, a = 41 cm =…

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