The equilibrium constant for the reaction below is 0.02 mol dm-3 at 298.000 K.Fructose 1,6-diphosphate _ glyceraldehyde 3-phosphate + dihydroxyacetone phosphateCalculate ΔG°.Provide answer to two decimal places and as J mol-1.

The equilibrium constant for the reaction below is 0.02 mol dm-3 at 298.000 K.Fructose 1,6-diphosphate _ glyceraldehyde 3-phosphate + dihydroxyacetone phosphateCalculate ΔG°.Provide answer to two decimal places and as J mol-1.

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter10: Fuels, Organic Chemicals, And Polymers

Section: Chapter Questions

Problem 119QRT

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Question

The equilibrium constant for the reaction below is 0.02mol dm^-3 at 298.000 K.

Fructose 1,6-diphosphate _ glyceraldehyde 3-phosphate + dihydroxyacetone phosphate

Calculate ΔG°.

Provide answer to two decimal places and as J mol^-1.

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