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- H3C CI C=C H2N I O (R)-enantiomer O (Z) isomer O (S)-enantiomer O (E) isomer O meso compoundjust part c thanks8. Identify the stereochemical relationship between the structural pairs shown below as (A) identical structures that are not meso; (B) identical structures that ARE meso; (C) structures that are enantiomers; or (D) structures that are diastereomers. a) b) H3C c) CH3 Br H. CH3 Br Br CH3 H. CI Holl H Cill Cl- CH3 Br H. CI CH3 HO. H. H3C Cl H3C- H- H. CH3 Cl a) b) c) 9. Identify the stereochemical relationship between the structural pairs shown below as (A) identical structures that are not meso; (B) identical structures that ARE meso; (C) structures that are enantiomers; or (D) structures that are diastereomers. a) b) c) CH2CH3 NH2 HO CH3 H3C. CH3 Cl HO H;C CH2CH3 F. F H;C. CI H H,N -CH3 CH3 NH2 H3C Br H2N C1 H3C CH3 CH3 H;CH,C- Cl F H. H Br CH,CH3 CH3 a) b) c)
- Which statement is correct about stereoisomers A, B, and C? H- CI CH3 S S CH3 A CI -H CI H A and B are enantiomers, C is a meso compound. A and C are enantiomers, B is a meso compound. A, B, and C are all meso compounds. Band C are enantiomers, A is a meso compound. CH3 R R CH3 B -H - CI H- H CH3 S R CH3 C CI -CIWhich structures below represent meso compounds?(d) EtO 1. Name each compound, showing stereochemistry where relevant: (a) Ph Ph (b) CH3(CH2);CN (c) NHCH, (d) EtO OEt (e) CI Cl
- What is the stereochemical configuration of the enantiomer of (2S, 4R)-2, 4-octanediol? (A diol is a compound with two —OH groups.)cis-1,2-Dimethylcyclohexane is optically inactive even though it has two chirality centers. Explain.Two conformations of cis-l, 3-dimethylcyclobutane are shown. What is the difference between them, and which do you think is likely to be more stable?
- label the stereocenters r,s,e,z and specify if any are meso. whats are the products to each orher? draw the chair conformationd and explain which one is the most stable for both products. are ha and hb homo/enantio/diasterio/hetero topic? also hc and hd.Are these structures diastereomers, me so, same compound, or enantiomers ?correct stereoisomers for the reaction
