In a soap preparation experiment, 100gm of vegetable oil was used with 5gm of NaOH. Calculate the efficiency of the reaction and the amount of the soap produced. When the amount of the produced glycerol was determined 0.1moles. The fatty acid was C17H30O2(MW 266g/mol) and glycerol C3H8O3 (MW 92g/mol)

In a soap preparation experiment, 100gm of vegetable oil was used with 5gm of NaOH. Calculate the efficiency of the reaction and the amount of the soap produced. When the amount of the produced glycerol was determined 0.1moles. The fatty acid was C17H30O2(MW 266g/mol) and glycerol C3H8O3 (MW 92g/mol)

EBK A SMALL SCALE APPROACH TO ORGANIC L

4th Edition

ISBN:9781305446021

Author:Lampman

Publisher:Lampman

Chapter24: Preparation Of Soap

Section: Chapter Questions

Problem 1Q

See similar textbooks

Similar questions

Aspirin (acetylsalicylic acid, C9H8O4) is made by reacting salicylic acid (C7H6O3) with acetic anhydride [(CH3CO)2O]: C7H6O3(s)+ (CH3CO)2O(l) → C9H8O4(s) + CH3COOH(l) In one preparation, 3.077 g of salicylic acid and 5.50 mL of acetic anhydride react to form 3.281 g of aspirin. (a) Which is the limiting reactant (d of acetic anhydride = 1.080 g/mL)? (b) What is the percent yield of this reaction? (c) What is the percent atom economy of this reaction?
Aspirin (acetylsalicylic acid, C9H8O4) is made by reacting salicylic acid (C7H6O3) with acetic anhydride [(CH3CO)2O]: C7H6O3(s) + (CH3CO)2O(l) → C9H8O4(s) + CH3COOH(l)In one preparation, 3.077 g of salicylic acid and 5.50 mL of aceticanhydride react to form 3.281 g of aspirin. (a) Which is the limitlimiting reactant (d of acetic anhydride = 1.080 g/mL)? (b) What is the percent yield of this reaction?
The overall reaction for microbial conversion of glucose to L-glutamic acid is: C6H1206 + NH3 +1.5 O2 →C5H,NO4 + CO2 + 3H20 (glucose) (glutamic acid) a) If 18 grams of glutamic acid are produced, how many grams of ammonia are required? Assume 100% conversion of ammonia b) What mass of glucose is required to produce 25 g of glutamic acid? Assume 100% conversion of glucose Atomic weights: C=12, H=1, N=14, O=16.
C12H22O11 + H2O → C6H12O6 What type of reaction is this? Is the lactose to glucose reaction a redox reaction?
In a synthesis of biodiesel, 8.7 g sunflower oil was used and 7.8 FAMEs was recovered. How much linoleic acid is generated using the cart below?
A 0.200-g fat was reacted with excess ICl. The remaining ICl was reacted with KI to form I2 and the iodine formed was titrated against a 0.100-N Na2 S2O3 and consumed 43.5-mL of the titrant. A blank analysis was performed, and 65.0-mL of the titrant was used. Calculate the iodine number of the fat.
The basal metabolic rate (BMR) of a person is the daily energy use for a person at rest to keep our essential processes running. An equation for the BMR for a woman is shown below. BMR (kcal) = (4.54 × weight in lb) + (15.9 × height in inches) - (5 × age in years) - 161 Determine the basil metabolic rate of a 136 lb, 5' - 4" 20 year old woman in watts. You will need to convert from kcal to joules.
Write the structure(s) for the organic product(s) of the carbohydrate reaction below. ball & stick V HOCH₂ но HO +labels -O HOCH₂ **** Te OH HO Sucrose CH₂OH OH Ag2O in aq. NH3 or Br₂ in H₂O, pH 6
After 1.805g of sucrose C12H22O11 reacted with NaCIO3, 2.87g NaCIO3 remained at the end of the reaction. Here is the balanced equation: 8 NaCIO3 + C12H22O11 -> 8NaCl + 12 CO2 + 11 H20 (NaCIO3=106.44g/mol, C12H22O11=342.34g/mol, NaCl=58.44g/mol, CO2=44.01g/mol, H2O=18.02g/mol) What was the initial mass of NaCIO3 used in the reaction?
Most sugars can act as reducing agents. Could the dichromate reaction shown in equation (1) be used to determine the alcohol concentration in beer? Why or why not? Equation 1: 2 K2Cr2O7 + 8 H2SO4 + 3 CH3CH2OH → 2 Cr2(SO4)3 + 2 K2SO4 + 3 CH3COOH + 11 H2O. (1)
20 MgBr +0=C=O Ⓡ product HCLH₂O → ??
Kidney stones are crystals of calcium oxalate that form in the kidney, ureter, or bladder. Small kidney stones are passed out of the body easily, but larger kidney stones may block the ureter causing severe pain. If the [Ca2+] in blood plasma is 5 × 10-3 M, what [C2O42-] must be present to form a kidney stone? (Calcium oxalate Ksp = 2.3 x 10-9)