Ideal Solutions: Raoult's Law tion Solutions Practice Problem 1 An aqueous solution of exsiccated ferrous sulfate was prepared by adding 41.50 g of Fe2SO4to enough water to make 1000mL of solution at 18°C. The density of the solution is 1.0375 and the molecular weight of Fe2SO4 is 151.9 g. (hint: density-mass/volume) Calculate: Molarity = n = mw n = IL 410-6.3563 Exbica 1519 = 0.273/125 1.Molarity Molality= 2.Molality 3.Mole fraction of Fe2SO4 and water 4.Percentage by weight of Fe2SO4 Solid lines repit

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Chapter13: Solutions And Their Behavior
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I need help with 2,3, and 4 assuming i did 1 correct please. 

Ideal Solutions: Raoult's Law
tion
Solutions
Practice Problem 1
An aqueous solution of exsiccated ferrous sulfate was prepared by
adding 41.50 g of Fe2SO4to enough water to make 1000mL of
solution at 18°C. The density of the solution is 1.0375 and the
molecular weight of Fe2SO4 is 151.9 g. (hint: density-mass/volume)
Calculate:
Molarity = n = mw
n =
IL
410-6.3563 Exbica
1519
=
0.273/125
1.Molarity
Molality=
2.Molality
3.Mole fraction of Fe2SO4 and water
4.Percentage by weight of Fe2SO4
Solid lines repit
Transcribed Image Text:Ideal Solutions: Raoult's Law tion Solutions Practice Problem 1 An aqueous solution of exsiccated ferrous sulfate was prepared by adding 41.50 g of Fe2SO4to enough water to make 1000mL of solution at 18°C. The density of the solution is 1.0375 and the molecular weight of Fe2SO4 is 151.9 g. (hint: density-mass/volume) Calculate: Molarity = n = mw n = IL 410-6.3563 Exbica 1519 = 0.273/125 1.Molarity Molality= 2.Molality 3.Mole fraction of Fe2SO4 and water 4.Percentage by weight of Fe2SO4 Solid lines repit
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