The curved beam is subjected to a bending moment of as shown. Determine the maximum compressive and tensile stresses in the section. Take M = 900 N.m, r¡ = 300 mm, a = 100 mm, b = 150 mm, c = 15 mm, and d = 20 mm. d TM a C Select one: - 5.81 MPa. and 5.81 MPa. - 3.01 MPa. and 3.74 MPa. D
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- This is not a quiz question. It is part of a study review with the solution given.very urgent pls4.3 The composite shaft, consisting of aluminum, copper, and steel sections, is subjected to the loading shown. Determine the displacement of end A with respect to end D and the normal stress in each section. The cross-sectional area and modulus of elasticity for each section are shown in the figure. Neglect the size of the collars at Band C. 3.50 kip 1.75 kip 1.50 kip 2.00 kip Steel BL 3.50 kip 1.75 kip Aluminum Copper Est = 29 (10)³ Ksi -18 in- -12 in- -16 in- Ecu = 18 (10)3 Ksi ABC = 0.12 in? Eal = 10(10)³ Ksi AcD = 0.09 6in² = 0.09 in? AAB
- 1. The composite shaft, consisting of aluminum, copper, and steel sections, is subjected to the loading shown. Determine the displacement of B with respect to C and the normal stress in each section. The cross-sectional area and modulus of elasticity for each section are shown in the figure. Neglect the size of the collars at B and C. Aluminum Eal = 70 GPa AAB = 58 mm² 9 kN A Copper Ecu = 126 GPa ABC = 77 mm² 450 mm 16 kN 斤。 16 kN -300 mm BL Steel Est = 200 GPa ACD = 39 mm² 8 kN 8 kN -400 mm 7 kNLink AB, of width b = 2 in. and thickness t = 1414 in., is used to support the end of a horizontal beam. The average normal stress in the link is -18 ksi and the average shearing stress in each of the two pins is 12 ksi. Determine the average bearing stress (ksi). **The way I had solved it was that I used the given normal stress to first find the P force needed to plus into my bearing stress formula. I still however need the diameter. The answer key says to use the given shear stress equation to find the diamter, how do you know to use that and not the shear stress formula again?X A purse hook is used to hang a handbag from the edge of a table with L = 50 mm. If the cross section at a-a has a diameter of d = 3 mm and the hook is supporting a purse with a mass of 3 kg, determine the normal stress profile. For what value of y (using the coordinates pictured for section a-a) with the normal stress be zero. If it is never zero enter "nde" for "not defined". N -L→ a. a AB C Follow sign convention that tension is positive and compression is negative. Normal stress at point A, σA= MPa Normal stress at point B, σB = MPa Normal stress at point C, σc = MPa y position where normal stress equals zero = mm Section a-a d
- C-S at E: 40 mm TB The pipe assembly is subjected to the loads shown. Determine the state of 1 kN 30 mm stress at point A on cross-section E and show the results on a volume element. (Ans: 0A = -5.615 MPa, Ta = 5.372 MPa) 0.4 m X 0.3 m B 0.5 m 0.1 m 0.1 m 60" E 0.25 m 2 kNDetermine the normal stress in each section of the assembly. The diameter of the solid shaft of each section is 0.50 inches. Give the answer in Ib/in?. Assume Point A is a fixed support and the block at A is rigid. Indicate if it is in tension or compression. 3.50 kip 1.75 kip 5.00 kip B 3.50 kip A 1.75 kip 18 in. 12 in.- 16 in: CAR = units %3D IINEED ASAP THANK YOU
- Question 4: Two wrenches are used to tighten the pipe. If the pipe is made from a material having an allowable shear stress of Tallow = 85 MPa, check the allowable force for external and internal diameter of pipe and determine the allowable maximum force P that can be applied to each wrench. The pipe has an outer diameter of 25 mm and inner diameter of 20 mm. 250 mm B 250 mm Figure 4 Answer: Torque = 0.5P, Polar moment of inertial J = 2.26 x 108 m4, outer diameter PS %3D 307.36N, inner diameter P S 384.2 N, Pallowable = 307.36NThe rectangular bar is connected to the support bracket with a 26-mm-diameter pin. The bar width is w=60 mm and the bar thickness is 15 mm. Each side of the bracket has the same dimensions as the bar. The average shear stress in the pin cannot exceed 120 MPa, the bearing stress in the bar cannot exceed 120 MPa, and the bearing stress in the bracket cannot exceed 120 MPa. Determine the maximum value of Pmax that can be supported by the structure. Answer: Pmax KNplease very urgent i will give u good feedback