Homework Help is Here – Start Your Trial Now!
Engineering
Mechanical Engineering
The shear force V at a cross section just to the right of A is equal to Ra = 8.2 kN. Moving to the right, the shear force remains constant until we reach the first point load at 3 m. The shear force then drops by 5 kN to 3.2 kN. The shear force remains constant until we reach the start of the UDL at 3 m. The shear force then decreases linearly by 1000 N/m over 4 m to -0.8 kN. The shear force remains constant until we reach the second point load at 7 m. The shear force then drops by 5 kN to -5.8 kN. Finally, the shear force jumps up by Rb = 5.8 kN to zero at B. draw diagram to show workings

The shear force V at a cross section just to the right of A is equal to Ra = 8.2 kN. Moving to the right, the shear force remains constant until we reach the first point load at 3 m. The shear force then drops by 5 kN to 3.2 kN. The shear force remains constant until we reach the start of the UDL at 3 m. The shear force then decreases linearly by 1000 N/m over 4 m to -0.8 kN. The shear force remains constant until we reach the second point load at 7 m. The shear force then drops by 5 kN to -5.8 kN. Finally, the shear force jumps up by Rb = 5.8 kN to zero at B. draw diagram to show workings

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
See similar textbooks
icon
Related questions
Question

The shear force V at a cross section just to the right of A is equal to Ra = 8.2 kN. Moving to the right, the shear force remains constant until we reach the first point load at 3 m. The shear force then drops by 5 kN to 3.2 kN. The shear force remains constant until we reach the start of the UDL at 3 m. The shear force then decreases linearly by 1000 N/m over 4 m to -0.8 kN. The shear force remains constant until we reach the second point load at 7 m. The shear force then drops by 5 kN to -5.8 kN. Finally, the shear force jumps up by Rb = 5.8 kN to zero at B.

draw diagram to show workings

Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY
SEE MORE TEXTBOOKS