In Python: story building. For this case, the analysis is limited to horizontal motion of the structure. Using Newton'ssecond law, force balances can be developed for this system asdt²m₁d²x₂=+k·x₁ + = (x2-x₁)m₁m3 = 8000 kgmk3 = 1800 kN/mk₂m₁ = 10,000 kg-(x3 - x2)m|k₂ = 2400 kN/mm2= (x2 − x3 )-dt²m₁ = 12,000 kgmk₁ = 3000 kN/mm3dt² m2d²x3_k3· (x₁ − x 2 ) +-=-Simulate the dynamics of this structure from t = 0 to 20 s, given the initial condition that the velocity ofthe ground floor is dx1/dt = 1 m/s, and all other initial values of displacements and velocities are zero.Present your results as two time-series plots of (a) displacements and (b) velocities. And develop a three-dimensional phase-plane plot of the displacements (X1, X2, X3). Use following functions:import matplotlib.pyplot as pltfrom mpl_toolkits.mplot3d import Axes 3D

First, let's import the necessary libraries and set up the simulation time range:import…

Answered: story building. For this case, the…

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter7: Arrays

Section7.5: Case Studies

Problem 15E

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(Conversion) An object’s polar moment of inertia, J, represents its resistance to twisting. For a cylinder, this moment of inertia is given by this formula: J=mr2/2+m( l 2 +3r 2 )/12misthecylindersmass( kg).listhecylinderslength(m).risthecylindersradius(m). Using this formula, determine the units for the cylinder’s polar moment of inertia.
(Civil eng.) The maximum load that can be placed at the end of a symmetrical wooden beam, such as the rectangular beam shown in Figure 2.20, can be calculated as the following: L=S1dc L is the maximum weight in lbs of the load placed on the beam. S is the stress in lbs/in2. I is the beam’s rectangular moment of inertia in units of in4. d is the distance in inches that the load is placed from the fixed end of the beam (the “moment arm”). c is one-half the height in inches of the symmetrical beam. For a 2” × 4” wooden beam, the rectangular moment of inertia is given by this formula: I=baseheight3=12=24312=10.674 c=(4in)=2in a. Using this information, design, write, compile, and run a C++ program that computes the maximum load in lbs that can be placed at the end of an 8-foot 24 wooden beam so that the stress on the fixed end is 3000lb/in2. b. Use the program developed in Exercise 9a to determine the maximum load in lbs that can be placed at the end of a 3” × 6” wooden beam so that the stress on the fixed end is 3000lb/in2.
(Civil eng.) Modify the program written for Exercise 9 to determine the maximum load that can be placed at the end of an 8-foot I-beam, shown in Figure 2.21, so that the stress on the fixed end is 20,000lbs/in2. Use the fact that this beam’s rectangular moment of inertia is 21.4 in4 and the value of c is 3 in.
(Conversion) Determine which of the following equations can’t be valid because they yield incorrect unit measurements: a.F=mab.F=m( v 2 /t)c.d=( at 2 )d.d=vte.F=mvtF=force(N)m=mass( kg)a=acceleration( m/s 2 )v=velocity( m/s)t=time(s)
(Numerical analysis) Here’s a challenging problem for those who know a little calculus. The Newton-Raphson method can be used to find the roots of any equation y(x)=0. In this method, the (i+1)stapproximation,xi+1,toarootofy(x)=0 is given in terms of the ith approximation, xi, by the following formula, where y’ denotes the derivative of y(x) with respect to x: xi+1=xiy(xi)/y(xi) For example, if y(x)=3x2+2x2,theny(x)=6x+2 , and the roots are found by making a reasonable guess for a first approximation x1 and iterating by using this equation: xi+1=xi(3xi2+2xi2)/(6xi+2) a. Using the Newton-Raphson method, find the two roots of the equation 3x2+2x2=0. (Hint: There’s one positive root and one negative root.) b. Extend the program written for Exercise 6a so that it finds the roots of any function y(x)=0, when the function for y(x) and the derivative of y(x) are placed in the code.

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