+(n) = 6 + (n − 1) + 4 + (n-2) donde: +(0) = 0 +(1) = 4√5
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solve recursion where t(0) = 0 and t(1) = 4 sqrt 5
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- expression for 2sin(n)cos(n) - sin(2π) O O O O sqrt(sqrt(2*M_PI)) O 3*tan(0.2) 2*sin(M_PI)*cos(M_PI) - sin(2*M_PI) O 0.8/0.9What is the minimum number of multiplications needed to generate x60 when starting from x? (you may only use terms of x to solve this problem, x * x = x2 is one multiplication, x2 * x2 leaves us at 2 multiplications, …)(100 N3+N and 10 N) has a Big-Oh of N. Choose one: Is it true or false?
- (n+4)(n+2) +1 belongs to: 2. O 0 (n) O 0 (n * log(n)) O 0 (nª) 0 0 (n²)Suppose you are given an array whose first n – f(n) elements are sorted, but whose last f(n) are not. How would you sort the entire array in O(n) time if f(n) is defined as follows? Be specific with your answer.Convert (111) 2 = (__) 10
