stoichonettie amounts of nitrog ad hydroger I mol Nada 3 md H2) ore feed to a realton standard free eegy chaye (Gibbs free energy) of reaction at 700K old 20 ber pieres-535315/ mol desomine equilibriun Constor(t) and the percotconersion of nitroger to ammoraa Cextentof realtion).12 + 3H2 2NH31 (atm) =750.061qual to the molar mass
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- I CottizO, ,+ L6O2-76ocOz+ Lott2+362.5 KJ what are the molors masses You You might need ? H2O? +20?Assume that 1.00 mL (1.02 g) of crude product mixture is obtained from the reactionbefore the washing steps, and the distribution constant of the product mixture in brine isK = (Cmixture/Cbrine) = 50.0. Assuming that after mixing the product mixture volume isstill 1.00 mL (i.e., the volume lost is small), and the volume of the first brine wash layeris 2.00 mL. What mass (grams) of product mixture is lost (dissolves) in the first brinewash? (See Technique 13.2, p 53.) Show work.< Week 8-1 X Week 8-1 X C 2 https://app.101edu.co K Formula Bara | PDF: SIF: Caf + 1 - 131 Sunny A Z "7 S ALEKS-13 x A ALEKS-Ti A ALEKS-TX Week 8-1 X m X Ksp 1.7 x 10. 36 x 10 - 4.3 x 10 3.5 x 10- x - Exam No.: x co DESU Calc X(427) mam xLog In | Fe x # Q Search Question 8 of 16 Which of the following salts would have the greatest solubility in water? _____________ __________ S L hp الالا alt A) BaF₂ B) PbF₂ C) SrF₂ D) CaF₂ ال A ctri لا pause < G Aktiv Chen a backspace X ● ه به enter GWhich oft X+ 3 T ما دیا ... T shift end 1 7 home 1 A ے h 1:0
- C Solubility of potassium nitrate in water Sample calculation of the solubility (show work for trial 1): Trial Solubility of KNO3 | [g KNO3/100g H20.] = || ||| IV1J R = 8.314 mol·K F = 96,485 mol AG = AG° + RT · In(Q) ΔΕ ΔΕ-). In(Q) Half Reaction (Note: All given as reduction) E° (V) 02 (g) + 4 H"(aq) + 4 e 2 H20 (1) 1.229 |Z2 (s) + 2 e → 2Z° (aq) 0.426 3+ (aq) + 3 е A' → A (s) 0.292 2 H20 (I) + 2 e H2 (g) + 2 OH¯ (aq) - 0.828 G2+ (aq) + 2 e G (s) - 1.245 (aq) + 2 e¯ → M (s) - 1.893 Using a U-tube, a student sets up a non-spontaneous electrochemical cell with a battery connected to two carbon electrodes that are submerged in 1 MMZ2 (aq) solution (M is a metal and Z is an anion composed of the newly discovered element Z). Use the reference information given in the table above to answer the following three questions. Question 11 The electrode connected to the red wire (negative terminal on the battery) will... o produce bubbles and the pH will increase. o produce M (s) on the electrode and the pH will not change. o produce bubbles and the pH will decrease. o produce M (s) on the electrode and the pH will decrease. Question 12 The electrode…
- - 144 / Natural Sciences / Chemistry And Polymer Science / Chemie zzes / Oplossingsewewig | Solubility Equilibria A solution contains 0.002 M Ag* and 1.6 x 105 M Zn2*, and the ions need to be separated. For this purpose co- is added to the solution so that both Ag,CO3 (Ksp = 8.1 x 10-12) and ZnCO3 (Ksp = 1.0 x 10-10) can precipitate from the solution. What will the concentration of co; be just before the first salt starts to precipitate. (Please give your answer with 2 significant figures.) Answer CheckExpeniment and name Chemical formula Cobalt (11) nitzate Co(NOs)2 Buldatance Aane and dhemical farmula mm, q/mo! 182.95g lmol Fruihal volume , L Iniial concentrahion measure d, mal/L Number of mole's and massof mass Of solute 500ML 0.876 mollL 0 -438 mol Colw0z to Concentration after eventahom affer evapo 1.461 mal L Can you please explatn to calculate how the 180.19) cduo wsas arrived at ? Thanks assJ R = 8.314 mol·K F = 96,485 mol AG = AG° + RT · In(Q) ΔΕ ΔΕ-).In(Q) Half Reaction (Note: All given as reduction) E° (V) 02 (g) + 4 H"(aq) + 4 e¯ → 2 H20 (1) 1.229 Z2 (s) + 2 e 2z° (aq) 0.426 (aq) + 3 е A (s) 0.292 2 H20 (1) + 2 e G2* (aq) + 2 e → H2 (g) + 2 OH¯ (aq) - 0.828 2+ G (s) - 1.245 M2+ (aq) + 2 e → M (s) - 1.893 A student constructs a voltaic electrochemical cell with two metal electrodes [metal G and metal A] in their respective aqueous nitrate solutions [G(NO3)2 and A(NO3)3]. Use this information, as well as the reduction potentials in the table above to complete each statement below. The number of electrons transferred per mole of reaction in this cell is.. Your answer should be a number with no units. Question 6 Diluting the half-cell solution will decrease the measured cell potential. o cathode O anode