None The van der Waalsequation of state(P + ñ³ ³) (V - nb) = nRT(A) 10 cm³.mol'.(C)1 cm³.mol'contains a term representing a “molecular size". Theapproximate magnitude of this term is(B) 10°³ cm³ -mol'.(D)10³ cm³.mol'.

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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6. Using dimensional analysis, show how 0.082057 Latm mol. K Significant figures note: the last digit on both values has been rounded. NOTE: 1 J = 1 N-m = 1 kg.m², and 1 Pa = 1 N m² is equal to 8.3145 or 1 kg m.s mol - K
(a) Use the following data for NH3 (g) at T = 273 K to evaluate B2P (T). (Here Z is the compressibility factor, PV/RT). P (bar) 0.10 0.20 0.30 0.40 0.50 0.60 0.70 Note: You will need to fit this data to a least-squares line. (b) At standard temperature (273.15 K), the density of O₂ varies with pressure as indicated in the table below: P (bar) 0.25331 0.50663 0.75994 1.01325 Z-1 1.519 x 10-4 3.038 x 10-4 4.557x 10-4 6.071 x 10-4 7.583 x 10-4 9.002 x 10-4 1.0551 x 10-3 2 p(g/L) 0.356985 0.714154 1.071485 1.428962 Use this data to find the second virial coefficient, B2v, of oxygen. Note that mo2 = 31.9988 Daltons. (Hint: It will be useful to determine the molar volume from each value of p.)
4. (a) Determine the reduced pressure (P,), volume (V,), and temperature (T, ) for a 50 L sample of water at 23 bar and 400 K. For H2O gas, Te = 647.14 K, P. = 220.64 bar, and Vc=55.95 L. (b) Determine the pressure, volume and temperature for a sample of hydrogen which is in a corresponding state with the H2O in part (a). For hydrogen, Te = 32.98 K, Pc = 12.93 bar and mc =64.20 L.
lodine pentoxide is used as a reagent to determine the amount of carbon monoxide present in a gaseous sample. The sample is passed over heated iodine pentoxide. The products of this process are carbon dioxide and iodine. The iodine formed is extracted and added to an excess of sodium thiosulfate solution of known concentration. The remaining sodium thiosulfate is then determined by titration with a solution of iodine of known concentration. 1₂(aq) + 25₂0₂²-(aq) → 21-(aq) + SÃO²-(aq) In an analysis, a 2.00 m³ sample of gas was used and the resultant iodine extracted and added to 20 cm³ of a 0.0400 mol dm-³ solution of sodium thiosulfate, an excess. The resultant solution was then titrated against a solution of iodine of concentration 0.0100 mol dm-³. The volume of iodine solution required for complete reaction was 21.60 cm³.
+ |/ 00 %24 D. Two bulbs are connected by a stopcock. The 7.50 L bulb contains nitric oxide (NO) at a pressure of 0.340 bar, and the 2.50 L bulb contains oxygen (O,) at a pressure of 0.510 bar. 02 ON After the stopcock is opened, the gases mix and react to produce nitrogen dioxide (CON) 2 NO(g) + 0,(g) – 2 NO,(g) Considering that the volume remains unchanged during the experiment, how does the total pressure in the bulbs change if the reaction is allowed to go to completion? The total pressure will remain constant. O There is not enough information to determine how the total pressure will change. O The total pressure will decrease. O The total pressure will increase. MacBook Pro ( The %23 %24 7. 4. 5. 3. R %3D K. H. B C. option command MOSISO
A gas mixture contains 4.5 mol Br, and 33.1 mol F,. (a) Compute the mole fraction of Br, in the mixture. (b) The mixture is heated above 150°C and starts to react to give BrFs: Br2(g) + 5 F2(g) –→ 2 BrF;(g) At a certain point in the reaction, 2.2 mol BrF5 is present. Determine the mole fraction of Br2 in the mixture at that point.
tiv Chemistry esc + • https://app.101edu.co X O E Q Aktiv Chemistry A 2 What is the temperature, in K, of 0.250 moles of krypton in a 5.00 L vessel at 1.39 atm? W S #3 20 F3 E X D 4 Lab - Alum 000 F4 R F C 5 F5 T × | + Question 11 of 13 G Y & 7 H U 8 DII FB J 9 8 F9 K 1 4 7 기 +/- 0
1.1 (a) A sample of air occupies 1.0 L at 25 °C and 1.00 atm. What pressure is needed to compress it to 100 cm’ at this temperature? 1.2(a) A perfect gas undergoes isothermal compression, which reduces its volume by 2.20 dm³. The final pressure and volume of the gas are 5.04 bar and 4.65 dm', respectively. Calculate the original pressure of the gas in (a) bar, (b) atm. 1.3 (a) To what temperature must a 1.0 L sample of a perfect gas be cooled from 25 °C in order to reduce its volume to 100 cm³? 1.4(a) A sample of 255 mg of neon occupies 3.00 dm at 122 K. Use the perfect gas law to calculate the pressure of the gas. 1.7(a) In an attempt to determine an accurate value of the gas constant, R, a student heated a container of volume 20.000 dm³ filled with 0.251 32 g of helium gas to 500°C and measured the pressure as 206.402 cm of water in a manometer at 25°C. Calculate the value of R from these data. (The density of water at 25°C is 0.997 07 g cm; the construction of a manometer is…
A certain gas obeys the equation of state PVm RT(1 + bP), where b is a constant. Prove that for this gas (a) (dU/dV)T = bP2; (b) CP,m - CV,m = R(1 + bP)^2; (c) mJT = 0
The quantity of oxygen that can dissolve in water depends on the temperature of the water. (So thermal pollution influences the oxygen content of w water temperature T. S (mg/L) 20 16 12 8 4 0 8 16 24 32 40 T (°C) 0 (a) What is the meaning of the derivative S'(7)? What are its units? S'(T) is the rate at which temperature changes with respect to time. The units are °C/s. S(T) is the rate at which oxygen solubility changes with respect to the water temperature. The units are (mg/L)/°C. O S'(T) is the rate at which temperature changes with respect to the oxygen solubility. The units are °C/(mg/L). OS'(T) is the current level of oxygen solubility for a given temperature. The units are mg/L. OS'(T) is the rate at which oxygen solubility changes with respect to the time. The units are (mg/L)/s. (b) Estimate the value of S'(32) and interpret it. (Round your answer to three decimal places.) S(32)
Q1/ The ideal gas equation of state is given by: PV = nRT Where: P is the pressure (atm), V is the volume (L), 7 is the temperature (K), R=0.08206 (L atm)/(mol K) is the gas constant, and n is the number of moles. Real gases, especially at high pressures, deviate from this behavior. Their responses can be modeled with the van der Waals equation: nRT V-nb Where a and b are material constants. For CO₂ a 3.5924 L'atm/mol², and b=0.04267 L/mol. Calculate P from both equations for CO₂ gas with 40 values of V between 0.01 and 1.5 and display the results in: 1- Three-column table where the values of Vand both P are displayed in the first, second, and third columns, respectively. 2-Plot V versus both P in two different plots in the same figure with a solid line, black color, with circle marker. Add a title, labels, and the grid to the plot. Make all texts bold with font size of 13. Take T=298K and n=3 moles. nº a + √² P
The volume of HCI is 100 mL , mass of solid added is 1.008g, moles of solid 0.0276 Mol, mass of HCI is 100g, initial temperature is 21.8 degrees Celsius, Final temperature is 30.7 degrees Celsius, Calculate q rxn(= -mc Delta T of HCI),

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The van der Waals equation of state (P + ñ³ ³) (V - nb) = nRT (A) 10 cm³.mol'. (C) 1 cm³.mol' contains a term representing a “molecular size". The approximate magnitude of this term is (B) 10°³ cm³ -mol'. (D) 10³ cm³.mol'.