12.8 When 1.00 g of urea [CO(NH2)2] is dissolved in 200 g of solvent A, the A freezing point is lowered by 0.250°C. When 1.50 g of the nonelectrolyte Y is dissolved in 125 g of the same solvent A, the A freezing point is lowered by 0.200°C. (a) Find the molecular weight of Y. (b) The freezing point of A is 12°C, and its molecular weight is 200. Find Afus of A.
12.8 When 1.00 g of urea [CO(NH2)2] is dissolved in 200 g of solvent A, the A freezing point is lowered by 0.250°C. When 1.50 g of the nonelectrolyte Y is dissolved in 125 g of the same solvent A, the A freezing point is lowered by 0.200°C. (a) Find the molecular weight of Y. (b) The freezing point of A is 12°C, and its molecular weight is 200. Find Afus of A.
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter10: Solutions
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Problem 76QAP: The freezing point of 0.10 M KHSO3 is -0.38C. Which of the following equations best represents what...
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![12.8 When 1.00 g of urea [CO(NH2)2] is dissolved in 200 g of
solvent A, the A freezing point is lowered by 0.250°C. When
1.50 g of the nonelectrolyte Y is dissolved in 125 g of the same
solvent A, the A freezing point is lowered by 0.200°C. (a) Find
the molecular weight of Y. (b) The freezing point of A is 12°C,
and its molecular weight is 200. Find Afus of A.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d7dc701-b654-4339-995f-9e7ccdd48dfe%2F3d22827c-bd01-4b11-9dcb-62c6395472a7%2Fjngdzd9_processed.png&w=3840&q=75)
Transcribed Image Text:12.8 When 1.00 g of urea [CO(NH2)2] is dissolved in 200 g of
solvent A, the A freezing point is lowered by 0.250°C. When
1.50 g of the nonelectrolyte Y is dissolved in 125 g of the same
solvent A, the A freezing point is lowered by 0.200°C. (a) Find
the molecular weight of Y. (b) The freezing point of A is 12°C,
and its molecular weight is 200. Find Afus of A.
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