Square loop of copper wire- ks = side length ххх х х х X x x xBx Above this line: B uniform and horizontal s = side length Below this line: B = 0 d = wire diameter Urerminal

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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In the figure below, the conducting loop has fallen a short distance and is now falling at a constant velocity, vterminal. The loop has sides of length s=0.50 m, mass 30.0 g, and resistance R=1.00 Ω. If B=7.50 T and is directed into the page, answer the following question:

What is the magnitude of the force pulling down on this loop and according to Lenz’s Law, in which direction will an induced current in the loop travel? Make sure to show how you know and all your work.

Square loop of
copper wire-
ks = side length
X X X X X X
x x xBx x
Above this line:
B uniform and horizontal
s = side
length
Below this line:
B = 0
d = wire diameter
Uterminal = ?
Transcribed Image Text:Square loop of copper wire- ks = side length X X X X X X x x xBx x Above this line: B uniform and horizontal s = side length Below this line: B = 0 d = wire diameter Uterminal = ?
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